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tresset_1 [31]
3 years ago
12

Helppppp please will give brainlist ​

Mathematics
1 answer:
NeX [460]3 years ago
7 0

Answer:

D or answer 4                   y=-5/2x+7

Step-by-step explanation:

Well we can first start of by finding the y-intercept.

Note that when x=0, you can find your y-intercept.

Knowing this, and looking at the table, 7 is the y-intercept because when y=7, x=0.

So we can eliminate choices 'a' and 'c,' or answers 1 and 3, because they have the y-intercept as -7, when it's just 7.

Please know that in the equation:

y = mx + b

y = y-coordinate or any given point

mx = slope

b = y-intercept

Now we must find slope

To find the slope we need to do:

(y2 - y1) / (x2 - x1) or rise/run

The two coordinates I choose to use is (0, 7) and (6, -8).

(-8 - 7) / (6 - 0) = -5/2

-5/2 is the slope

Finally, look for an equation that has 7 as the y-intercept and -5/2 as the slope.

Answer: D or answer 4

You might be interested in
1. What is the measure in radians for the central angle of a circle whose radius is 6 cm and intercept arc length is 5.4 cm?
fgiga [73]
Hello!

1.
find circumferece
c=2pir
c=2*6*pi=12pi
intercept is 5.4

2pi radians=all

part/whole=part/whole
5.4/12pi=x/2pi
times both sides by 12pi
5.4=6x
divide both sides by 6
0.9=x
answer is 0.9 radians



2. 
assuming 9pi/5 radians

find circumference
c=2pir
c=2*26.9*pi
c=53.8pi

arc/circumference=(9pi/5)/2pi

x/(53.8pi)=(9pi/5)/(2pi)
x/(53.8pi)=18/5
times both sides by 53.8pi
x=608.46266 m
about x=608.46 m


Hope this Helps! Have A Wonderful Day! :) 
5 0
3 years ago
A rocket is launched from the top of a 99-foot cliff with an initial velocity of 122 ft/s.
Harman [31]
Remember that c is the initial height. Since we the rocket is in a 99-foot cliff, c=99. Also, we know that the velocity of the rocket is 122 ft/s; therefore v=122
Lets replace the values into the the vertical motion formula to get:
0=-16 t^{2} +122t+99
Notice that the rocket hits the ground at the bottom of the cliff, which means that the final height is 99-foot bellow its original position; therefore, our final height will be h=-99
Lets replace this into our equation to get:
-99=-16 t^{2} +122t+99
-16 t^{2} +122+198=0

Now we can apply the quadratic formula t= \frac{-b+or- \sqrt{ b^{2} -4ac} }{2a} where a=-16, b=122, and c=198
t= \frac{-122+or- \sqrt{ 122^{2}-(4)(-16)(198) } }{(2)(-16)}
t= \frac{-122+ \sqrt{27556} }{-32} or t= \frac{-122- \sqrt{27556} }{-32}
t= \frac{-122+166}{-32} or t= \frac{-122-166}{-32}
t= \frac{-11}{8} or t=9

Since the time can't be negative, we can conclude that the rocket hits the ground after 9 seconds.
5 0
4 years ago
Read 2 more answers
I need some help. Please
Ilya [14]

Are you able to ask your teacher?

7 0
3 years ago
A plane is flying at the height of 5000 meter above the sea level. at a particular point, it is excatly above a submarine floati
AnnyKZ [126]

Answer:

3800 meters

Step-by-step explanation:

3 0
3 years ago
5 increased by t operation and algebraic expressions
zubka84 [21]

increased means addition

 so 5+t

5 0
3 years ago
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