All categories

3 years ago

A trapezoid is a quadrilateral with exactly two parallel sides. is it True or False

Mathematics

1 answer:

cupoosta [38]3 years ago

7 0

False, a Trapezoid only has 1 parallel side.

You might be interested in

Every year, the value of a property in singapore appreciates by 15% of its value in the previous year. If the value of the prope

tensa zangetsu [6.8K]

Answer:

629 510$

Step-by-step explanation:

$899300 - (30% of $899300)

cuz its two years away from 2010 so it will have gone up 30 % so to rewind time, just go back 30%

4 0

3 years ago

Read 2 more answers

Round your answer to the nearest hundredth.<br><br> 13.48x − 200 < 256.12

wolverine [178]

Answer:

Step-by-step explanation:

13.48x − 200 < 256.12

Using the addition property , add 200 to both sides

That's

13.48x + 200 - 200 < 256.12 + 200

13.48x < 456.12

<u>Divide both sides by 13.48</u>

$\frac{13.48x}{13.48} < \frac{456.12}{13.48} \\ x < \frac{456.12}{13.48} \\ \: \: \: x < 33.83679$

We have the final answer as

x < 33.84 to the nearest hundredth

Hope this helps you

4 0

3 years ago

Read the following excerpt from a personal narrative essay. Based on the excerpt, what did the writer learn from her personal ex

Tresset [83]

The best answer is b

4 0

3 years ago

What are the zeros of the polynomial function?

Genrish500 [490]

Hello from MrBillDoesMath!

Answer:

x = 2 and 10

Discussion:

Approach 1:

20 = (-10)*(-2) and (-10) + (-2) = -12 the coefficients of the polynomial. Hence

x^2 -12x + 20 = ( x- 2) * ( x-10)

Approach 2:

From the quadratic formula ( a = 1, b = -12, c = 20)

x = ( -(-12) +\- sqrt( ((-12)^2 - 4*1*20) ) / (2 * 1)

= ( 12 +\- sqrt( 144-80) ) /2

= (12 +\- sqrt(64) ) /2

= (12 +\- 8 ) /2

x = ( 12 + 8) /2 = 20/2 = 10

x = ( 12 - 8)/ 2 = 4/2 = 2

Thank you,

MrB

5 0

4 years ago

Read 2 more answers

The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th

ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

$|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}$

By doing so, we find:

$|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}$

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

$|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1$

4 0

3 years ago