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nalin [4]
3 years ago
5

I need help with properties of rhombus, rectangles and squares ​

Mathematics
1 answer:
Flauer [41]3 years ago
6 0

Answer:

  • rhombus
  • x = 70
  • y = 5

Step-by-step explanation:

A quadrilateral with 4 same-length sides is a <em>rhombus</em>.

(If the corner angles are also 90°, then the rhombus is also a square. That is not the case here.)

__

Adjacent angles are supplementary, so ...

  x° = 180° -110° = 70°

Sides are the same length, so ...

  2y = y+5

  y = 5 . . . . . subtract y

_____

If part of the picture was cut off, the right side of the figure may be something other than 2y. If so, formulate the equation appropriately and solve for y.

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Solve for j: j + j / 2 + J + 5 = 45
Georgia [21]

Answer:

j:5j/2+5=45 Or j=16 how you put it was a little confusing

5 0
2 years ago
What value of c makes x2 + 6x + c a perfect square trinomial? 3 6 9 12
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The answer is 3 jehfhdhhedhhshshdhhsgdjshshdhdh
5 0
3 years ago
Three consecutive integers can be represented by n, n + 1, and n + 2. if the seum of three consecutive integers is 57, what are
Helen [10]
Sum means add
sum of the 3 is
n+n+1+n+2

it add to 57
n+n+1+n+2=57
3n+3=57
minus 3 both sides
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8 0
3 years ago
A circle is centered at the point (5, -4) and passes through the point (-3, 2).
zepelin [54]

Answer:

(x-5)^2+(y+4)^2=100

Step-by-step explanation:

As we know the given points

Center = (5, -4)

and

Point on circle = (-3,2)

The distance between point on circle and center will give us the radius of circle

So,

The formula for distance is:

\sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1})^{2}}\\Taking\ center\ as\ point\ 1\ and\ the\ other\ point\ as\ point\ 2\\d=\sqrt{(-3-5)^{2}+(2-(-4))^{2}}\\d=\sqrt{(-8)^{2}+(2+4)^{2}}\\d=\sqrt{(-8)^{2}+(6)^{2}}\\\\d=\sqrt{64+36}\\d=\sqrt{100} \\ d=10\\So\ the\ radius\ is\ 10

The standard form of equation of circle is:

(x-h)^{2}+(y-k)^{2}=r^{2}

where h and k are the coordinates of the center. So putting in the value:

(x-5)^{2}+(y-(-4))^{2}=(10)^{2}\\(x-5)^{2}+(y+4)^{2}=100

8 0
3 years ago
Write 0.414141414141 as a fraction?
igor_vitrenko [27]

Answer:

The fraction is 41/99.

Step-by-step explanation:

The steps are :

let \: x \: be \: fraction,

x = 0.414141.....

100x = 41.414141.....

100x - x = 41.414141.....  \:  -  \: 0.414141.....

99x = 41

x =  \frac{41}{99}

4 0
3 years ago
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