X^+8x+6 Find the value that makes each trinomial a perfect square

R is the midpoint of OP and QR is perpendicular to OP in the diagram below

dezoksy [38]

Answer:

24 in

Step-by-step explanation

Using pythagorean theorem, since OP is 20 inches and has a midpoint. RP= 10 and OR=10. The hypotenuse is given as 26 so do 26^2=10^2+a. 676= 100+a^2, subtract 100 from both sides. square root of 576 is 24

7 0

3 years ago

A truck driver is 2 hours into 1,346-Mile drive and has driven 125 Miles s far. Which of the following is the number of miles th

Mila [183]

The answer is 1,121 miles

6 0

3 years ago

5. Graph the given system of linear inequalities on the coordinate plane below. (2 points)sy <-3x - 4< 21-15NA11 2 3 4 5 6

xxTIMURxx [149]

ANSWERS

(5) Graph:

(6) Solutions: (-1, -5) and (-2, -7)

Not solutions: (1, 1) and (-4, -3)

EXPLANATION

(5) To graph this system, first, we have to graph each of the inequalities. Both are linear, so we have to graph each line with a dashed line - this is because they are "less than" the line, so the line is not included, and shade the area below each of them.

The first inequality is y < -3x-4,

The second inequality is y < 2x - 1,

The graph of the system is the area shared by both graphs,

(6) Any point that is inside the shaded area is a solution of the system. For example, points (-1, -5) and (-2,-7) are solutions to the system.

On the other hand, any point outside that area, or on the dashed lines is not a solution. For example, points (1, 1) and (-4, -3) are not solutions

8 0

1 year ago

Jennifer order 5 pairs of shoes online. All shoes were the same price and she paid $375 which included shipping. Choose the stat

Oksanka [162]

Answer:

Step-by-step explanation:

The answer would be B C A

5 0

3 years ago

Read 2 more answers

A survey said that 3 out of 5 students enrolled in higher education took at least one online course last fall. Explain your calc

marysya [2.9K]

Answer:

a) 60% probability that student took at least one online course

b) 40% probability that student did not take an online course

c) 12.96% probability that all 4 students selected took online courses.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they took at least one online course last fall, or they did not. The probability of a student taking an online course is independent of other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

3 out of 5 students enrolled in higher education took at least one online course last fall.

This means that $p = \frac{3}{5} = 0.6$

a) If you were to pick at random 1 student enrolled in higher education, what is the probability that student took at least one online course?

This is P(X = 1) when n = 1. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{1,1}.(0.6)^{1}.(0.4)^{0} = 0.6$

60% probability that student took at least one online course.

b) If you were to pick at random 1 student enrolled in higher education, what is the probability that student did not take an online course?

This is P(X = 0) when n = 1.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{1,1}.(0.6)^{0}.(0.4)^{1} = 0.4$

40% probability that student did not take an online course

c) Now, consider the scenario that you are going to select random select 4 students enrolled in higher education. Find the probability that all 4 students selected took online courses

This is P(X = 4) when n = 4.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{4,4}.(0.6)^{4}.(0.4)^{0} = 0.1296$

12.96% probability that all 4 students selected took online courses.

3 0

3 years ago