Ask question

Ask question

All categories

uranmaximum [27]

3 years ago

15

4/7x+5/14x=39 plleeeease

1 answer:

Yanka [14]3 years ago

6 0

Answer:

15568

Step-by-step explanation:

sub in 39 for x and then multiply

You might be interested in

A pizza delivery shop averages 20 minutes per delivery with a standard deviation of 4 minutes. What is the probability that a pi

Vlada [557]

... ......... . .........

4 0

3 years ago

Read 2 more answers

Evaluate log base 6 1/216

Musya8 [376]

The answer should be 2 but i really don't know so its 2

\

4 0

3 years ago

Find the geometric mean of 2 and 3

Sav [38]

The first step in solving this problem is taking 2 and 3 and multiplying them (2 * 3 = 6) .
Now, for the second step, we will cube it. Since there are 2 numbers, we are going to use the 2nd root (2sqrt(6)) This will give us: 4.89897948557 or 5 if you would round it. This would be the Geometric Mean.

7 0

3 years ago

What is the slope the line?

laila [671]

Answer:

the slope is 3/4x

Step-by-step explanation:

if you need it in slope intercept form too its y=3/4x-1

4 0

3 years ago

The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given

slavikrds [6]

Answer:

a) $\frac{dm}{dt} = -k\cdot m$ , b) $m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$ , c) $m(t) = 10\cdot e^{-\frac{t}{2438.155} }$ , d) $m(300) \approx 8.842\,g$

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

$\frac{dm}{dt} = -k\cdot m$

b) The general solution is found after separating variables and integrating each sides:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $\tau$ is the time constant and $k = \frac{1}{\tau}$

c) The time constant is:

$\tau = \frac{1690\,yr}{\ln 2}$

$\tau = 2438.155\,yr$

The particular solution of the differential equation is:

$m(t) = 10\cdot e^{-\frac{t}{2438.155} }$

d) The amount of radium after 300 years is:

$m(300) \approx 8.842\,g$

4 0

3 years ago

Read 2 more answers