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uranmaximum [27]
3 years ago
15

4/7x+5/14x=39 plleeeease

Mathematics
1 answer:
Yanka [14]3 years ago
6 0

Answer:

15568

Step-by-step explanation:

sub in 39 for x and then multiply

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Write the exponential equation for the given situation. A tennis tournament starts with 128 participants. Each round, half of th
inysia [295]

Answer:

y= 128(1-.5)^t

Step-by-step explanation:

6 0
3 years ago
María drinks 400 ml of water every hour. How many hours will it take her to drink 2 L of water?
JulijaS [17]

Hello,

The correct answer is 5 Liters.

2 Liters of water = 2000 Milliliters.

If she drinks 400 Milliliters per hour, then you do 2000 ÷ 400 to work out the number of hours.

2000 ÷ 400 = 5

Hope this helps!!!! :)

5 0
3 years ago
angel is visiting a cousin 280 miles away from nashville. he’s already driven 70 miles in the first hour. at that speed how many
Tpy6a [65]

Answer:

  3 hours

Step-by-step explanation:

Angel's remaining distance is ...

  280 mi - 70 mi = 210 mi

At 70 miles per hour, it will take ...

  (210 mi)/(70 mi/h) = 3 h

to cover the remaining distance.

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The appropriate relationship is ...

  time = distance/speed

4 0
3 years ago
-y+8y=?<br> What is the answer please?
Tpy6a [65]

Answer:

y = -6/7

x = 6/49

Step-by-step explanation:

-7x -y = 0

7x +8y = -6

Add the two equations together to eliminate x

-7x -y = 0

7x +8y = -6

-----------------------

   7y = -6

Divide by 7

7y/7 = -6/7

y = -6/7

Now we need to find x

-7x -y = 0

-7x -(-6/7) =0

-7x +(6/7) =0

-7x +6/7 -6/7 =0-6/7

-7x = -6/7

Divide each side by -7

-7x/-7 = -6/7 *-1/7

x = 6/49

3 0
3 years ago
Suppose P(t)represents the population of a certain mosquito colony, where. t is measured in days. The current population of the
Darina [25.2K]

Answer:

The estimated size of the population in 10 days is of 1372 mosquitos.

Step-by-step explanation:

Population after t days:

The population after t days is given by:

P(t) = P(0)e^{rt}

In which P(0) is the initial population and r is the growth rate, as a decimal.

P(0)=574.

So

P(t) = 574e^{rt}

P'(0)=50

P^{\prime}(t) = 574re^{rt}

Since P'(0)=50

574r = 50

r = \frac{50}{574}

r = 0.0871

So

P(t) = 574e^{0.0871t}

Estimate the size of the population in 10 days

This is P(10).

P(10) = 574e^{0.0871*10} = 1372

The estimated size of the population in 10 days is of 1372 mosquitos.

4 0
3 years ago
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