First draw a line on the smallest number, and one on the largest. then calculate the midpoint (n+1)/2 the value, and draw that line in the middle. calculate upper quartile and lower quartile and draw lines on them. draw a line between the tops of the quartiles and one between the bottom, and from the middle of the lines to the minimum and maximum. sorry if not explained well
he needs at least 5800
5800/725
8
so he must sell at least 8 cars
There are only 45 cars on the lot, so that is the max he can sell
Choice C
8<=x<=45
Answer:
102 steps/1minute
In seconds it would be 102/60 which can be reduced to 17/10, or 1.7
The applicable formula is;
A = P(1+r)^nt
Where
A = Accumulate amount
P = Initial invested amount
r = Annual interest rate
n = Number of payments in a year
t = Time in years
First part of the question: Accumulated amount after 18 years
Substituting;
A = 1000(1+0.01)^12*18 = $8,578.61
Since the car costs $15,000 and the amount in the bank after 18 years is $8,578.61, Anthony wouldn't be able to afford the car.
Second part of the question: The amount which should have been deposited for Antony to afford the car after 18 years
15,000 = P (1+0.01)^12*18
15,000 = P*8.5786
P = 15,000/8.5786 = $1,748.54
Therefore, for Antony to afford the $15,000 after 18 years, the mum should have deposited $1,748.54.
