Ask question

Ask question

All categories

3 years ago

7

Which of the following is not a type of pulley system

2 answers:

andreev551 [17]3 years ago

8 0

D advantageousA pulley is a wheel on an axle or shaft that is designed to support movement and change of ... The drive element of a pulley system<span> can be a rope, cable, belt, or chain that runs over the pulley.</span>

NikAS [45]3 years ago

3 0

I think the answer is D: advantageous

You might be interested in

What kind of stars make up the galactic nucleus?

Hatshy [7]

I think the correct answer would be old and metal poor stars are found in the galactic nucleus. This nucleus us a region in the center of a galaxy which contains a higher luminosity than other parts. It produces very high amounts of energy. Hope this helps.

4 0

3 years ago

Read 2 more answers

Four solid plastic cylinders all have radius 2.55 cm and length 5.70 cm. Find the charge of each cylinder given the following ad

vazorg [7]

Answer:3

Explanation:idk

5 0

3 years ago

The breeze during a sunny day at the beach is usually a result of _________________________________________.

N76 [4]

C, Land heats and cools faster than water!

3 0

3 years ago

Read 2 more answers

A speed skater is sliding across the ice at a speed of 19 m/s when she encounters a rough patch of ice that is 2.0 m wide. As sh

Stells [14]

Answer:

$-9.25 m/s^2$

Explanation:

The motion of the skater is a uniformly accelerated motion, so we can find the deceleration by using the following suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

In this problem, we have:

u = 19 m/s is the initial velocity of the skater

v = 18 m/s is the final velocity of the skater

s = 2.0 m is the displacement

Solving for a, we can find the acceleration:

$a=\frac{v^2-u^2}{2s}=\frac{18^2-19^2}{2(2.0)}=-9.25 m/s^2$

And the negative sign tells us that the acceleration is in the opposite direction to the motion (so, it is a deceleration)

5 0

4 years ago

A parallel-plate capacitor has plates of area A. The plates are initially separated by a distance d, but this distance can be va

ohaa [14]

Answer:

d' = d /2

Explanation:

Given that

Distance = d

Voltage =V

We know that energy in capacitor given as

$U=\dfrac{1}{2}CV^2$

$C=\dfrac{\varepsilon _oA}{d}$

$U=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d}\times V^2$

If energy become double U' = 2 U then d'

$U'=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d'}\times V^2$

$2U=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d'}\times V^2$

$2\times \dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d}\times V^2=\dfrac{1}{2}\times \dfrac{\varepsilon _oA}{d'}\times V^2$

2 d ' = d

d' = d /2

So the distance between plates will be half on initial distance.

7 0

3 years ago