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3 years ago

28. Ken and Musa shared a cake such that Ken got twice the size

Physics

1 answer:

ratelena [41]3 years ago

3 0

Answer:

$Musa = \frac{1}{3}$

$Ken = \frac{2}{3}$

Explanation:

Given

$Ken = 2 * Musa$ --- Ken's share

Required

The fraction each got

Since they both shared a cake, we have:

$Ken + Musa = 1$

Substitute: $Ken = 2 * Musa$

$2 * Musa+ Musa = 1$

Factorize

$Musa(2+ 1)= 1$

$Musa(3)= 1$

Divide both sides by 3

$Musa = \frac{1}{3}$

Recall that: $Ken = 2 * Musa$

$Ken = 2 * \frac{1}{3}$

$Ken = \frac{2}{3}$

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A single-phase electrical load draws 600KVA at 0.6 power factor lagging. a) Find the real and reactive power absorbed by the loa

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Answer:

(a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

Explanation:

Given that,

Power factor = 0.6

Power = 600 kVA

(a). We need to calculate the reactive power

Using formula of reactive power

$Q=P\tan\phi$ ...(I)

We need to calculate the $\phi$

Using formula of $\phi$

$\phi=\cos^{-1}(Power\ factor)$

Put the value into the formula

$\phi=\cos^{-1}(0.6)$

$\phi=53.13^{\circ}$

Put the value of Φ in equation (I)

$Q=600\tan(53.13)$

$Q=799.99\ kVAR$

(b). We draw the power triangle

(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95

Using formula of reactive power

$Q'=600\tan(0.95)$

$Q'=9.94\ KVAR$

We need to calculate the difference between Q and Q'

$Q''=Q-Q'$

Put the value into the formula

$Q''=799.99-9.94$

$Q''=790.05\ KVAR$

Hence, (a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

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3 years ago

Plants appear green because they do not absorb the green wavelengths of light what happens to those green light waves when they

Arlecino [84]

The green wavelengths are reflected, causing green to be the only color we see in certain parts of plants.

Best of luck, my man.

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3 years ago

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3 years ago

A bicycle tire has a radius of 0.23 m. the tire spins at a constant speed with a centripetal acceleration of 42 m/s2. what is th

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Answer:

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2 years ago

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If you pull a resistant puppy with its leash in a horizontal direction, it takes 80 N to get it going. You can then keep it movi

netineya [11]

Answer:

The coefficient of static friction between the puppy and the floor is 0.7273.

Explanation:

The horizontal force applied to move the puppy from a steady state has to be greater than the force of static friction, after it is moving the force needs to be equal to be greater than the force of dynamic friction in order to maintain its movement. The force of static friction is given by:

$F_s = \mu_s*N$

Where $F_s$ is the static friction force, $\mu_s$ is the coefficient of static friction and $N$ is the normal force. Since there's no angle on the flor the normal force is equal to the weight of the puppy, therefore, $N = 110\text{ N}$ , to make the puppy moving we need to use a force of 80 N, therefore, $F_s = 80 \text{ N}$ , so we can solve for the coefficient as shown below:

$80 = \mu_s*110\\\mu_s = \frac{80}{110} = 0.7273\\$

The coefficient of static friction between the puppy and the floor is 0.7273.

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3 years ago