**Answer:**

**121km/h**

**Explanation:**

Let speed of boat=xkm/h

Speed of water flow=33 km/h

Speed upstream=(x-33)km/h

Speed downstream=(x+33)km/h

Time=44 hrs

Time =77 hrs

We have to find the speed of boat.

Using the formula

Upstream distance=Downstream distance

**Hence, the speed of boat=121km/h**

Distance is the total length of an object's path. Displacement is the overall change in position, ie. how far an object is from its initial position.

The court is 30 m long, so a path going back and forth once is 60 m long. Going along this path 6 times totals 360 m.

The end point is the same as the starting point, so the displacement is 0 m.

**Answer:**

**Explanation:**

Given

mass of climber

Distance between rock and cliff=48.6 m

mass of rock

let T be the tension in the rope

Thus ------1

where a is the acceleration of system

Also for Rock

------2

From 1 & 2 we can say that

g+a=19.303 a

g=18.303 a

Thus climber is decelerating with

time to cover 48.6 m

t=13.47 s

**Explanation:**

The attached figure shows the position-time graph of a ladybug. We need to find the average speed of the ladybug between t = 4 s to t = 7 s.

We know that, the slope of a position-time graph gives velocity of an object. It can be given by :

In this case, the position of a ladybug at t = 4 s and at t = 7 s is the same i.e. 2 m.

**It means its velocity is equal to at this time or we can say that ladybug is at rest.**