A unit fraction is a fraction whose numerator is 1.
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➷ 12 : 40
==> 3 : 10
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Answer:
A graph showing a range of negative three to two on the x and y axes. A dotted line with arrows at both ends that passes through the x axis at two and runs parallel to the y axis. The graph is shaded to the left of the line.
Step-by-step explanation:
The inequality given is x < 2. This means x is less than two are the values that satisfy the equation.
The equation can be written as x=2 to identify the position where the line will pass. The line is dotted and will pass through x=2 to be parallel with the y-axis.
The second and third answers are not correct because the line should not be solid.
The first answer is not correct because the shaded part should be to the left of the line.
To find the area, we have to use the F.O.I.L. method to solve (3x-2)*(4x-7)
-> 12x^2-21x-8x+14
= 12x^2 - 29x + 14
So the area of the rectangle would be 12x^2 - 29x + 14.
<span>Hope this helps. If you have any questions, place it in the comment section below.</span>
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.
Let's consider a simple example of estimating the value of a general definite integral,

Split up the interval
![[a,b]](https://tex.z-dn.net/?f=%5Ba%2Cb%5D)
into

equal subintervals,
![[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]](https://tex.z-dn.net/?f=%5Bx_0%2Cx_1%5D%5Ccup%5Bx_1%2Cx_2%5D%5Ccup%5Ccdots%5Ccup%5Bx_%7Bn-2%7D%2Cx_%7Bn-1%7D%5D%5Ccup%5Bx_%7Bn-1%7D%2Cx_n%5D)
where

and

. Each subinterval has measure (width)

.
Now denote the left- and right-endpoint approximations by

and

, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are

. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints,

.
So, you have


Now let

denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

Factoring out

and regrouping the terms, you have

which is equivalent to

and is the average of

and

.
So the trapezoidal approximation for your problem should be