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laila [671]
3 years ago
9

What is 50 plus 30 divided by 4

Mathematics
2 answers:
cupoosta [38]3 years ago
8 0

Answer:

I believe that the correct answer is 57.5.

Step-by-step explanation:

If you do the problem straight up the answer will be 20, but if you use order of operations (or PEMDAS) the answer will be 57.5.

Aloiza [94]3 years ago
6 0

Answer: 57.5

Step-by-step explanation: The first thing you need to know about the order of operations is that multiplication and division come before addition and subtraction.

So in this problem, we are going to divide before we add.

Since 30 divided by 4 is 7.5, our next step will read 50 + 7.5 and 50 + 7.5 simplifies to 14.

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Write each fraction as a unit fraction<br> 12/84<br> 13/143<br> 23/138
alexandr1967 [171]
A unit fraction is a fraction whose numerator is 1.

\frac{12}{84}=\frac{12 \div 12}{84 \div 12}=\frac{1}{7} \\ \\&#10;\frac{13}{143}=\frac{13 \div 13}{143 \div 13}=\frac{1}{11} \\ \\&#10;\frac{23}{138}=\frac{23 \div 23}{138 \div 23}=\frac{1}{6}
7 0
3 years ago
How can "12 of 40" be written as a simplified ratio?
vitfil [10]
<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ 12 : 40

==> 3 : 10

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

5 0
3 years ago
Read 2 more answers
Graph x&lt;2.
bazaltina [42]

Answer:

A graph showing a range of negative three to two on the x and y axes. A dotted line with arrows at both ends that passes through the x axis at two and runs parallel to the y axis. The graph is shaded to the left of the line.

Step-by-step explanation:

The inequality given is x < 2. This means x is less than two are the values that satisfy the equation.

The equation can be written as x=2 to identify the position where the line will pass. The line is dotted and will pass through x=2 to be parallel with the y-axis.

The second and third answers are not correct because the line should not be solid.

The first answer is not correct because the shaded part should be to the left of the line.

5 0
3 years ago
Find the area of the rectangle below (3x-2) (4x-7)
Contact [7]
To find the area, we have to use the F.O.I.L. method to solve (3x-2)*(4x-7)

-> 12x^2-21x-8x+14

= 12x^2 - 29x + 14

So the area of the rectangle would be 12x^2 - 29x + 14.

<span>Hope this helps. If you have any questions, place it in the comment section below.</span>
4 0
3 years ago
Read 2 more answers
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
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