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2 years ago

Find the quotient of these complex numbers (5-7i)/(2-5i)

Mathematics

1 answer:

saul85 [17]2 years ago

5 0

Answer:

45/29+11/29i

Step-by-step explanation:

A P E X :D

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WINSTONCH [101]

Answer:

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Step-by-step explanation:

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2 years ago

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Apply the following transformations to the shape and draw the resulting shape

Morgarella [4.7K]

Answer:

Step-by-step explanation:

Take the coordinates(0,0)(2, -2)(6, -4)(4, -6) and cut each number in half. Then move each point left 3 and up 2.

4 0

3 years ago

*Find the formula of the series 1+2²+3²+4²+....+n²*<br>

Sophie [7]

The formula is $\frac{n(n+1)(2n+1)}{6}$

What are series?

In mathematics, we can describe a series as adding infinitely many numbers or quantities to a given starting number or amount.

We will find the formula as shown as below:

Let $S=1+2^2+3^2+4^2+................+n^2$

We know $(n+1)^3=n^3+3n^2+3n+1$

$(1+1)^3=1^3+3(1)^2+3(1)+1$

$(2+1)^3=2^3+3(2)^2+3(2)+1$

$(3+1)^3=3^3+3(3)^2+3(3)+1$

$(n+1)^3=n^3+3(n)^2+3(n)+1$

On adding

$2^3+3^3+4^3......(n+1)^3=(1^3+2^3+3^3+.....+n^3)+3(1^2+2^2+.....+n^2)+3(1+2+3....n)+(1+1+1+....+1)$

$2^3+3^3+4^3......(n+1)^3-(1^3+2^3+3^3+.....+n^3)=3S+\frac{3n(n+1)}{2}+(1+1+1+....+1)$

$(n+1)^3-1^3=3S+\frac{3n(n+1)}{2} +n$

$n^3+3(n)^2+3(n)+1-1=3S+\frac{3n(n+1)}{2} +n$

$2n^3+6n^2+6n=6S+3n^2+3n+2n$

$6S=2n^3+3n^2+n$

$6S=2n^2(n+1)+n(n+1)$

$6S=(n+1)(2n^2+n)$

$6S=n(n+1)(2n+1)$

$S=\frac{n(n+1)(2n+1)}{6}$

Hence, the formula is $\frac{n(n+1)(2n+1)}{6}$

Learn more about Series here:

brainly.com/question/24643676

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3 0

1 year ago

Simplify (-4b^3) (2b^5)

Agata [3.3K]

Hello! Sorry that it’s taken so long for someone to get to you but hopefully I am able to help!

Without the boring words and searching for the answer I’ll just give it to you

Answer: (-4b^3)(2b^5)

Please mark me brainliest !

4 0

2 years ago

Unit rate of 50 meters in 27.5 seconds

ElenaW [278]

50 meters/27.5 seconds = 1.818 meters /sec

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2 years ago

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