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Doss [256]
3 years ago
14

Fill in the numbers to find a Sum

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
4 0

Answer:

The numbers are -15 and 100

\frac{2}{10} +\frac{-15}{100} =\frac{5}{100}

Step-by-step explanation:

we have

\frac{2}{10} +\frac{x}{100} =\frac{5}{y}

Solve the left side

\frac{2}{10} +\frac{x}{100} =\frac{20+x}{100}

so

\frac{20+x}{100}=\frac{5}{y}

equate the numerators and the denominators

20+x=5 ------> x=5-20=-15

100=y -------> y=5

therefore

The numbers are -15 and 100

\frac{2}{10} +\frac{-15}{100} =\frac{5}{100}

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Solve the top equation to get on variable on one side
2x-y=6
-y=-2x+6
y=2x-6
then plug in the coordinate for x and y for both equations. if both equations are true then it’s a solution
2=2(2)+6
2=10

4+2=6

so it’s not a solution
4 0
3 years ago
Please help!!! ILL GIVE U BRAINLIEST.
Viktor [21]

Answer:

f(x) is translated by 4 units left.

Step-by-step explanation:

did it help ?

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6 0
2 years ago
Information on a sample of 362 college students is collected. The complete dataset is available at StudentSurvey. We see that 27
pishuonlain [190]

Answer:

So, we conclude that the best estimate for the difference in the proportion of smokers is 4.4%.

Step-by-step explanation:

We know that 27 of the 193 males in the sample smoke while 16 of the 169 females in the sample smoke.  

We have the following proportion:

27:x=193:100\%\\\\193x=27\cdot 100\\\\193x=2700\\\\x=\frac{2700}{193}\\\\x=13.9\%

So we get that 13.9% of men smoke.

We have the following proportion:

16:x=169:100\%\\\\169x=16\cdot 100\\\\169x=1600\\\\x=\frac{1600}{169}\\\\x=9.5\%

So we get that 9.5% of women smoke.

We get: 13.9%-9.5%=4.4%.

So, we conclude that the best estimate for the difference in the proportion of smokers is 4.4%.

6 0
3 years ago
Solve the inequality below for z . 5 − 8 ≥ z + 4
Tanya [424]

Answer:

sorry man i need pont

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Hhelp pls lol i don't understand​
sladkih [1.3K]

Answer:

m∠1= 80

m∠2= 100

m∠3= 80

Step-by-step explanation:

Given: m∠1= 2x +40

m∠2= 2y +40

m∠3= x +2y

m∠1 +m∠2= 180 (adj. ∠s on a str. line)

2x +40 +2y +40= 180

2x +2y+ 80= 180

2x +2y= 180 -80

2x +2y= 100

2(x +y)= 100

x +y= 100 ÷2

x +y= 50 -----(1)

m∠1= m∠3 (vert. opp. ∠s)

2x +40= x +2y

2x -x +40= 2y

x= 2y -40 -----(2)

Substitute equation (2) into (1):

2y -40 +y= 50

3y= 50 +40

3y= 90

y= 90 ÷3

y= 30

Substitute y= 30 into equation (2):

x= 2(30) -40

x= 60 -40

x= 20

m∠1

= 2x +40

= 2(20) +40

= 40 +40

= 80

m∠2

= 2y +40

= 2(30) +40

= 60 +40

= 100

m∠3

= x +2y

= 20 +2(30)

= 20 +60

= 80

Alternatively, since m∠1= m∠3,

m∠3

= m∠1 (vert. opp. ∠s)

= 80

5 0
3 years ago
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