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Doss [256]
3 years ago
14

Fill in the numbers to find a Sum

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
4 0

Answer:

The numbers are -15 and 100

\frac{2}{10} +\frac{-15}{100} =\frac{5}{100}

Step-by-step explanation:

we have

\frac{2}{10} +\frac{x}{100} =\frac{5}{y}

Solve the left side

\frac{2}{10} +\frac{x}{100} =\frac{20+x}{100}

so

\frac{20+x}{100}=\frac{5}{y}

equate the numerators and the denominators

20+x=5 ------> x=5-20=-15

100=y -------> y=5

therefore

The numbers are -15 and 100

\frac{2}{10} +\frac{-15}{100} =\frac{5}{100}

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Write each equation in standard form using integers? <br><br> y = 3x + 1<br><br> y = 4x - 7
Maru [420]

Answer:

The standard form of y = 3 x + 1 is         -3x + y = 1 .

The standard form of y  = 4x - 7 is         -4x + y = -7.

Step-by-step explanation:

Here the given equation are:

y = 3 x + 1

and y  = 4x - 7

The above equations are of the form:  y = m x + C

Now, the STANDARD FORM of the equation is Ax + By  = C

<u>Consider equation 1: </u>

y = 3 x + 1

or, y - 3x  = 1

or. -3x + y = 1

⇒ The equation  -3x + y = 1  is in STANDARD FORM.

<u>Consider equation 2: </u>

y = 4 x - 7

or, y - 4x  = -7

or. -4x + y = -7

⇒ The equation -4x + y = -7 is in STANDARD FORM.

3 0
2 years ago
Evaluate the expression when x=27 and y=16
abruzzese [7]

Answer:

43

Step-by-step explanation:

ok

6 0
2 years ago
What is the hcf of 45 and 100
Ira Lisetskai [31]

Answer:

45 100

/ \ / \

3 × 15 2×50

/ \ / \

3× 5 2×25

/ \

5×5

45 : 3×3×5

100: 2×2×5×5

common : 3×5

15

HCF: 15

6 0
2 years ago
PLZ PLZ PLZ HELP!!!!!!!!!!!!!!!!!!!!
tigry1 [53]
The answer would be C, 150 televisions. 
8 0
3 years ago
URGENT: the question is in the attachment below
joja [24]

Simultaneous equation refer to a pair of equations that are solved at the same time.

<h3>What is a simultaneous equation?</h3>

A  simultaneous equation refer to a pair of equations that are solved at the same time.

For problem 1;

x = 4 - y ------ (1)

y^2 = 3x + 19 ----- (2)

Substitute (1) into (2)

y^2 = 3(4 - y) + 19

y^2 = 12 - 3y + 19

y^2 +3y - 31 =0

y = 4.27 or -7.27

x = 4 - 4.27 = 0.27

or

x = 4 - (-7.27) = 11.27

For the second problem;

x = 7 - y

y^2 = 5x - 15

Substitute (1) into (2)

y^2 = 5(7 - y) - 15

y^2 =35 -5y -15

y^2 + 5y - 20 = 0

y =2.62 or -7.62

x = 7 - 2.62 = 4.38

OR

x=  7 - (-7.62) = 14.62

Learn more about simultaneous equation:brainly.com/question/16763389

#SPJ1

8 0
2 years ago
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