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mina [271]
3 years ago
15

Determine the relation of the following lines y = -2x +4 and y= -2x +1

Mathematics
1 answer:
Ivahew [28]3 years ago
7 0
They're parallel because they have the same slope.
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Use reasoning algebra to write the unknown factor
NARA [144]
I dont get it... lol
7 0
3 years ago
A team spent 20 mins on passing drills and 40 minuets ona shooting drill, what is the ratio of time spent on shooting drills to
aliya0001 [1]
20 minutes on passing .....40 minutes on shooting

ratio of time spent on shooting to passing....
these are not hard, u just have to pay attention to the wording...

the ratio of shooting to passing is 40/20 which reduces to 2/1 or 2:1 or
2 to 1 <===

but if it would have asked for passing to shooting, it would have been :
20/40 which reduces to 1/2 or 1:2 or 1 to 2

so ur answer is 2/1 or 2:1 or 2 to 1
6 0
3 years ago
One of the base angles of an isosceles triangle is 40°. Which is the triangle classification according to its
kozerog [31]

Answer:

C. Obtuse

Step-by-step explanation:

7 0
2 years ago
How many times is 3 in 43.999 than the value of the digit 3 in 42.103
Dennis_Churaev [7]

Answer:

1. 14.666 ¯ over the 3

2. 14.034 ¯ over the 3

Step-by-step explanation:

5 0
3 years ago
Given r(x) = 11/ (x - 42)
julsineya [31]

For a given function f(x) we define the domain restrictions as values of x that we can not use in our function. Also, for a function f(x) we define the inverse g(x) as a function such that:

g(f(x)) = x = f(g(x))

<u>The restriction is:</u>

x ≠ 4

<u>The inverse is:</u>

y = 4 + \sqrt{\frac{11}{x} }

Here our function is:

f(x) = \frac{11}{(x - 4)^2}

We know that we can not divide by zero, so the only restriction in this function will be the one that makes the denominator equal to zero.

(x - 4)^2 = 0

x - 4 = 0

x = 4

So the only value of x that we need to remove from the domain is x = 4.

To find the inverse we try with the general form:

g(x) = a + \sqrt{\frac{b}{x} }

Evaluating this in our function we get:

g(f(x)) = a + \sqrt{\frac{b}{f(x)} }  = a + \sqrt{\frac{b*(x - 4)^2}{11 }}\\\\g(f(x)) = a + \sqrt{\frac{b}{11 }}*(x - 4)

Remember that the thing above must be equal to x, so we get:

g(f(x)) = a + \sqrt{\frac{b}{11 }}*(x - 4) = x\\\\{\frac{b}{11 }} = 1\\{\frac{b}{11 }}*4 - a = 0

From the two above equations we find:

b = 11

a = 4

Thus the inverse equation is:

y = 4 + \sqrt{\frac{11}{x} }

If you want to learn more, you can read:

brainly.com/question/10300045

3 0
2 years ago
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