Answer:
the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
Step-by-step explanation:
From the five randomly selected students ; 160, 175, 163, 149, 153
mean average of the students = 160+175+163+149+153/5
= mean = x-bar = 800/5
mean x-bar = 160
from probability distribution, P(x-bar > 160) = P[ x-bar - miu / SD > 160 -150.8 /3.94]
P( Z>2.34) = from normal Z-distribution table
= 0.0096419
= 0.0096
hence the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
where SD = standard deviation = 3.94 and Miu = 150.8
Answer:
The answer is 
.
Step-by-step explanation:
To solve the inequality, start by solving for the variable 
.
To solve for the variable , subtract 
from both sides. The inequality will look like 
.
Then, divide both sides by 6.5 in order to get the variable by itself. The inequality answer will look like 
.
I’m sorry! I hope you do better next time.
Answer:
0.6 is your answer if you need explanation than comment me
