Answer:
![p\leq\$70.](https://tex.z-dn.net/?f=p%5Cleq%5C%2470.)
Step-by-step explanation:
The 1000 tickets will be sold when each ticket costs $60.
The manager wants to sell at least 800 tickets which is maximum
1000-800=200 tickets less than 1000.
Given that for 20 less tickets will be sold for every $1 increase in price.
So, 20x2=40 less tickets will be sold for $1x2=$2 increase in price.
Proceeding in a similar way, for any natural number n:
20 x n less tickets will be sold for $1 x n=$n increase in price.
Here, 200=20x10, so n=10
So, 20x10 less tickets will be sold for $1x10=$10 increase in price.
Hence, the manager can increase the price of each ticket up to $10.
So, to sell at least 800 tickets, the maximum price of each ticket can be $60+$10=$70.
Hence, the value of
is
![p\leq\$70.](https://tex.z-dn.net/?f=p%5Cleq%5C%2470.)