There are 17 hops in a hop, a skip, and a jump.
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How to perform changes of units?</h3>
We have the relations:
- 1 skip = 4 hops.
- 1 jump = 3 skips.
How many hops are in a hop, a skip and a jump?
So we have:
1 hop + 1 skip + 1 jump.
First, using the second relation we rewrite:
1 hop + 1 skip + 3 skips = 1 hop + 4 skips.
Now, using the first relation:
1 hop + 4 skips = 1 hop + 4*(4 hops) = 1 hop + 16 hops = 17 hops.
There are 17 hops in a hop, a skip, and a jump.
If you want to learn more about changes of units:
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This is cross multipication. Multiply 117 times 36 together for that you would use a calculator. You get 4221. Next step is to multiply x and 12 together that would be 12x.
4221= 12x
Divide by 12 on both sides:
x= 351
351 is # of trouts in the lake .
(1/3)^2 is 1/9 and 1/9*9 is 1
So 1
Answer: <u>16.</u> 21ft
<u>17.</u> 116.67mi or ≈117mi
<u>18.</u> 1,377,795in or 3,499.993m or ≈3500m
How we would calculate each of these: For number 16, you would set up a proportion of 1/3=7/x and then simplify this to 1x=21 which results in you dividing 1 from both sides of the equation and getting 21 as x, or the amount of feet. For number 17, you would do the same thing except with the different numbers. You set up another proportion. 3/50=7/x and then simplify to 3x=350. Divide the 3 on both sides and you get x=116.67mi to which you can round to 117mi if you like. For number 18, you must convert the 3.5 kilometers to inches and get 1,377,795in and then you can convert those inches into meters which would be 3,499.993m or you can round it to around 3500m.
