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-BARSIC- [3]
3 years ago
15

2.82 TONS ROUNDED TO THE NEAREST HUNDREDTH in tons

Mathematics
2 answers:
Leviafan [203]3 years ago
5 0
3.00 tons because you have to rounded it and see if the 8 is bigger then 5
ahrayia [7]3 years ago
3 0
2.82 rounded to the nearest hundredth would be the same 2.82 because your hundredth place is the 2 after the 8 and assuming the next digit over is 0 because nothing is there you would not round up.
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pychu [463]

Answer: Their equations have different y-intercept but the same slope

Step-by-step explanation:

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m_1 = \frac{q-p}{2011-2002} = \frac{q-p}{9}

Similarly, the slope of the line asses through the points (2,p) and (11,q) is,

m_2 = \frac{q-p}{11-2} = \frac{q-p}{9}

Since, m_1 = m_2

Hence, both line have the same slope.

Now, the equation of the line one having slope m_1 and passes through the point (2002,p) is,

y - p = \frac{q-p}{9}(x-2002)

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The y-intercept of the line one is (0, \frac{2000(p-q)}{9}+p)

Also, the equation of second line having slope m_2 and passes through the point (2,p)

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What is meant by algebraic equation​
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Answer:

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Read 2 more answers
Lamaj is rides his bike over a piece of gum and continues riding his bike at a constant rate time = 1.25 seconds the game is at
Hitman42 [59]

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. At time = 1.25 seconds, the gum is at a maximum height above the ground and 1 second later the gum is on the ground again.

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b. What is the height of the gum when Lamaj gets to the end of the block at t = 15.6 seconds?

c. When are the first and second times the gum reaches a height of 12 cm?

Answer:

Step-by-step explanation:

a)

We are being told that:

Lamaj rides his bike over a piece of gum and continues riding his bike at a constant rate. This keeps the wheel of his bike in Simple Harmonic Motion and the Trigonometric equation  that models the height of the gum in centimeters above the ground at any time, t, in seconds.  can be written as:

\mathbf {y = 34cos (\pi (t-1.25))+34}

where;

y =  is the height of the gum at a given time (t) seconds

34 = amplitude of the motion

the amplitude of the motion was obtained by finding the middle between the highest and lowest point on the cosine graph.

\mathbf{ \pi} = the period of the graph

1.25 = maximum vertical height stretched by 1.25 m  to the horizontal

b) From the equation derived above;

if we replace t with 1.56 seconds ; we can determine the height of the gum when Lamaj gets to the end of the block .

So;

\mathbf {y = 34cos (\pi (15.6-1.25))+34}

\mathbf {y = 34cos (\pi (14.35))+34}

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c)

When are the first and second times the gum reaches a height of 12 cm

This indicates the position of y; so y = 12 cm

From the same equation from (a); we have :

\mathbf {y = 34 cos(\pi (t-1.25))+34}

\mathbf{12 = 34 cos ( \pi(t-1.25))+34}

\dfrac {12-34}{34} = cos (\pi(t-1.25))

\dfrac {-22}{34} = cos(\pi(t-1.25))

2.27 = (\pi (t-1.25)

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Similarly, replacing cosine in the above equation with sine; we have:

\mathbf {y = 34 sin (\pi (t-1.25))+34}

\mathbf{12 = 34 sin ( \pi(t-1.25))+34}

\dfrac {12-34}{34} = sin (\pi(t-1.25))

\dfrac {-22}{34} = sin (\pi(t-1.25))

-0.703 = (\pi(t-1.25))

t = 2.527 seconds

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Answer:

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The elimination method is useful when you can eliminate one of the variable terms from an equation by adding or subtracting anot
Reil [10]
The answer is True. Hope this helps :)

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