Order of operations kbesbeienesbe

Vinil7 [7]

9514 1404 393

Answer:

7.84 to 8.16 ounces

Step-by-step explanation:

The difference between the actual amount in the bottle and the target amount of 8 ounces can be at most 2% of 8 ounces. That amount is ...

0.02×8 oz = 0.16 oz

The amount in the bottle can be this much higher:

8 + 0.16 = 8.16 . . . ounces

or, it can be that much lower:

8 - 0.16 = 7.84 . . . ounces

The range of values the bottle could contain is from 7.84 ounces to 8.16 ounces.

6 0

2 years ago

I have included a picture of the equation

Alchen [17]

Answer:

it's c , x= 1.5 or -4

2x^2 + 5x - 12 = 0

First factor the left side of the equation

(2x-3)(x+4)=0

Second, set the factors equal to 0

2x-3=0 or x+4=0

+3 +3 -4 -4

2x=3 -4

divide both side by 2 and you get 3/2 which equals 1.5

x=1.5 or x= -4

3 0

2 years ago

Rewrite the standard form equation below into slope-intercept form. 2x – 3y = 1

pychu [463]

The correct answer is y=2/3x-1/3

4 0

3 years ago

Find the area of the region enclosed by the graphs of the functions

Vaselesa [24]

Answer:

$\displaystyle A = \frac{8}{21}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Functions
Function Notation
Graphing
Solving systems of equations

Calculus

Area - Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

*Note:

Remember that for the Area of a Region, it is top function minus bottom function.

Step 1: Define

f(x) = x²

g(x) = x⁶

Bounded (Partitioned) by x-axis

Step 2: Identify Bounds of Integration

Find where the functions intersect (x-values) to determine the bounds of integration.

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

Lower bound: -1

Upper Bound: 1

Step 3: Find Area of Region

Integration

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx$
[Area] Rewrite [Integration Property - Subtraction]: $\displaystyle A = \int\limits^1_{-1} {x^2} \, dx - \int\limits^1_{-1} {x^6} \, dx$
[Area] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = \frac{x^3}{3} \bigg| \limit^1_{-1} - \frac{x^7}{7} \bigg| \limit^1_{-1}$
[Area] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = \frac{2}{3} - \frac{2}{7}$
[Area] Subtract: $\displaystyle A = \frac{8}{21}$