9514 1404 393
Answer:
   7.84 to 8.16 ounces
Step-by-step explanation:
The difference between the actual amount in the bottle and the target amount of 8 ounces can be at most 2% of 8 ounces. That amount is ...
   0.02×8 oz = 0.16 oz
The amount in the bottle can be this much higher:
   8 + 0.16 = 8.16 . . . ounces
or, it can be that much lower:
   8 - 0.16 = 7.84 . . . ounces
The range of values the bottle could contain is from 7.84 ounces to 8.16 ounces.
 
        
             
        
        
        
Answer:
it's c , x= 1.5 or -4
2x^2 + 5x - 12 = 0
First factor the left side of the equation
(2x-3)(x+4)=0
Second, set the factors equal to 0
2x-3=0 or x+4=0 
  +3  +3       -4  -4
2x=3           -4
divide both side by 2 and you get 3/2 which equals 1.5
x=1.5 or x= -4
 
        
             
        
        
        
The correct answer is y=2/3x-1/3
        
             
        
        
        
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Terms/Coefficients
- Functions
- Function Notation
- Graphing
- Solving systems of equations
<u>Calculus</u>
Area - Integrals
Integration Rule [Reverse Power Rule]:                                                                 
Integration Rule [Fundamental Theorem of Calculus 1]:                                      
Integration Property [Addition/Subtraction]:                                                          ![\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%20%7B%5Bf%28x%29%20%5Cpm%20g%28x%29%5D%7D%20%5C%2C%20dx%20%3D%20%5Cint%20%7Bf%28x%29%7D%20%5C%2C%20dx%20%5Cpm%20%5Cint%20%7Bg%28x%29%7D%20%5C%2C%20dx)
Area of a Region Formula:                                                                                     ![\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20A%20%3D%20%5Cint%5Climits%5Eb_a%20%7B%5Bf%28x%29%20-%20g%28x%29%5D%7D%20%5C%2C%20dx)
Step-by-step explanation:
*Note:
<em>Remember that for the Area of a Region, it is top function minus bottom function.</em>
<u />
<u>Step 1: Define</u>
f(x) = x²
g(x) = x⁶
Bounded (Partitioned) by x-axis
<u>Step 2: Identify Bounds of Integration</u>
<em>Find where the functions intersect (x-values) to determine the bounds of integration.</em>
Simply graph the functions to see where the functions intersect (See Graph Attachment).
Interval: [-1, 1]
Lower bound: -1
Upper Bound: 1
<u>Step 3: Find Area of Region</u>
<em>Integration</em>
- Substitute in variables [Area of a Region Formula]:                                     ![\displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20A%20%3D%20%5Cint%5Climits%5E1_%7B-1%7D%20%7B%5Bx%5E2%20-%20x%5E6%5D%7D%20%5C%2C%20dx) 
- [Area] Rewrite [Integration Property - Subtraction]:                                      
- [Area] Integrate [Integration Rule - Reverse Power Rule]:                            
- [Area] Evaluate [Integration Rule - FTC 1]:                                                     
- [Area] Subtract:                                                                                                
Topic: AP Calculus AB/BC (Calculus I/II)  
Unit: Area Under the Curve - Area of a Region (Integration)  
Book: College Calculus 10e
 
        
             
        
        
        
Answer:
3
Step-by-step explanation:
see image