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Luda [366]
3 years ago
13

Two jugs are similar. The smaller jug has radius 4cm and the bigger jug has radius

Mathematics
2 answers:
nexus9112 [7]3 years ago
8 0

Answer:

yuh

get into it

Step-by-step explanation:

ivolga24 [154]3 years ago
6 0

Given:

Two jugs are similar. The smaller jug has radius 4 cm and the bigger jug has radius 6 cm and surface area 125 cm².

To find:

The area of the smaller jug.

Solution:

If two figures are similar, then the ratio of their areas is proportional to the square of the corresponding sides of the figures.

Two jugs are similar. So,

\dfrac{\text{Area of smaller jug}}{\text{Area of bigger jug}}=\dfrac{(\text{Radius of smaller jug})^2}{(\text{Radius of bigger jug})^2}

\dfrac{\text{Area of smaller jug}}{125}=\dfrac{(4)^2}{(6)^2}

\dfrac{\text{Area of smaller jug}}{125}=\dfrac{16}{36}

\text{Area of smaller jug}=\dfrac{4}{9}\times 125

\text{Area of smaller jug}\approx 55.56

Therefore, the area of the smaller jug is about 55.56 cm².

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Points to the left of the y-axis have a negative x- value

Points to the right of the y-axis have a positive x- value

Points on the y-axis have an x- value of zero

C(- 4, 5), D(- 9, 9 ), J(- 9, 0) ← are the coordinates of the points

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