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Ierofanga [76]
3 years ago
5

How do write 412.638 using expanded form using decimals

Mathematics
1 answer:
Radda [10]3 years ago
7 0
412.638 using expanded form using decimals is :
4 x 100 + 1 x 10 + 2 x 1 + 6 x 0.1 + 3 x 0.01 + 8 x 0.001 Hope this helped you!
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2 is your answer duuuuuuuuuuuude

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Which of the following statements is NOT true?
yanalaym [24]

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the second one

Step-by-step explanation:

it is not 2/3 because it is 1/2

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2 years ago
Volume of a cylinder with a height of 8 and a width of 8
tangare [24]

Answer:

I am only in like 5th grade, but I'll do my best to answer this.

Step-by-step explanation:

Volume of a cylinder: πr^2h where "r" is the radius and "h" is the height

π * 4^2 because since the width is 8, half of that is the radius

π * 4^2 * 8 because you still have to multiply that by the height to find the full space inside

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3 years ago
Which plot has an outlier?
inna [77]

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girls

Step-by-step explanation:

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5 0
3 years ago
Assuming that the heights of college women are normally distributed with mean 64 inches and standard deviation 1.5 inches, what
professor190 [17]

Answer:

15.74% of women are between 65.5 inches and 68.5 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 64, \sigma = 1.5

What percentage of women are between 65.5 inches and 68.5 inches?

This percentage is the pvalue of Z when X = 68.5 subtracted by the pvalue of Z when X = 65.5.

X = 68.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{68.5 - 64}{1.5}

Z = 3

Z = 3 has a pvalue of 0.9987

X = 65.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{65.5 - 64}{1.5}

Z = 1

Z = 1 has a pvalue of 0.8413

So 0.9987 - 0.8413 = 0.1574 = 15.74% of women are between 65.5 inches and 68.5 inches.

8 0
3 years ago
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