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ASHA 777 [7]
3 years ago
10

20 POINTS BRAINLIEST

Mathematics
1 answer:
Ierofanga [76]3 years ago
4 0

Answer:

im pretty sure its c. 2 units left and 6 units up

Step-by-step explanation:

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If the area of the trapezoid below is 75 square units, what is the value of x?
4vir4ik [10]

Answer:

6 units

Step-by-step explanation:

The formula for a trapezoid is ((b1+b2)/2)h.

Here, we see b1 = 8 and b2 = 17.

If the area of the trapezoid is 75, we can make the equation :

75 = ((8+17)/2)x , where we would solve for x.

First, we simplify the right side of the equation :

75 = (25/2)x

Multiply both sides by 2 to get rid of the "/2"

150 = 25x

Then divide both sides by 25.

6=x

7 0
3 years ago
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
 How long would it take an ostrich to run from Halifax to Vancouver it did not have to stop it run 80 km an hour
Katen [24]

Answer:

76 hours and 37 minutes

this is a weird question btw

5 0
3 years ago
Linear equations word problems
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6 0
3 years ago
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What is13/250 as a decimal
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13/250 as a decimal is 0.052
7 0
3 years ago
Read 2 more answers
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