Answer: The answer to your question is 6
Step-by-step explanation:
To solve this problem we will use proportions. We will compare the largest right triangle and the medium size triangle.
                           Medium triangle                     Large triangle
hypotenuse                 y                                            9 + 3
adjacent size               9                                               y
- Write the proportions
                                   y/9 = (9 + 3)/y
-Solve for y
                                   y² = 9(12)
                                   y² = 108
                                   y =   
-Find the prime factors of 108
                                   108  2
 54 2
                                      27 3
                                       9  3
                                       3   3
                                        1
then,       108 = 2² 3³
-Expressthe root as fractional exponents
                                   2²/² 3²/² 3¹/²
-Simplification
                                    2(3)(3)¹/²
-Result
                                       6
 
        
             
        
        
        
Answer:
-5 
Step-by-step explanation:
think of it on a number line the number furthest to the left is always the smallest and the numbers to the right are bigger
 
        
                    
             
        
        
        
34.90 is the answer ♡♡
sorry typed the wrong number.
        
                    
             
        
        
        
Answer:
C
Step-by-step explanation:
Given:

Changing the division to multiplication by taking the reciprocal of the second fraction.

<u>The correct option is C</u>
 
        
                    
             
        
        
        
Answer:

Step-by-step explanation:
![\sf 3a^5-18a^3+6a^2\\\\HCF = 3a^2\\\\Take \ 3a^2 \ common\\\\= 3a^2(a^3-6a+2)\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%203a%5E5-18a%5E3%2B6a%5E2%5C%5C%5C%5CHCF%20%3D%203a%5E2%5C%5C%5C%5CTake%20%5C%203a%5E2%20%5C%20common%5C%5C%5C%5C%3D%203a%5E2%28a%5E3-6a%2B2%29%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>