To solve these type of problem you have to make the denominator the same or use the claculator.
let us do this problem by making the denominator the same.


So, now. the one with the largest numerator is the largest fraction
In this case,

is the largest which is equal to

.
So, the largest fraction is

.
Its can be divisible by 2
Answer:
(90 - y) °
Step-by-step explanation:
Complement of angle A = 90° - y° = (90 - y) °
Integers include negatives and decimals
whole numbers only inlcude counting numbers and 0
integers:2/3, 0.33333333, 94.345345345345..., -99
whole:0,1,2,3,4,5,6,7,8,9....