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Trava [24]
3 years ago
8

Andrew has a cell phone plan that provides 300 free minutes each month for a flat rate of $19. for any minutes over 200, andrew

is charged $0.39 per minute. which of the following piece-wise functions represents charges based on andrews cell phone plan?
Mathematics
1 answer:
natima [27]3 years ago
7 0

Answer:

f (x) = { 19 + 0.39(x - 300), x > 300

Step-by-step explanation:

Andrew has a cell phone plan that provides 300 free minutes each month for a flat rate of $19. For any minutes over 300, Andrew is charged $0.39 per minute. Let x be the number of minutes Andrew uses per month and f(x) be the charges based on Andrew's cell phone plan. If  then If  then first 300 minutes are free and each minute of next (x-300) minutes costs $0.39, therefore Hence, { 19 + 0.39(x - 300), x > 300

Hoped I helped

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Need help asap!! Tysmm
Levart [38]

Answer:

1) 9x-4

Step-by-step explanation:

7x+2x= 9x

-8+4= -4

9x-4

8 0
3 years ago
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Somebody who knows how to do this?? plz answer all the questions correctly thanks!
Ksju [112]

Answer:

a) 5/21

b) 4/21

c) 4/21

d) 8/21

Step-by-step explanation:

total number of coins: 21

a) number if dollars: 5

therefore fraction is 5/21

b) number of quarters: 4

therefore fraction is 4/21

c) number of dimes: 4

therefore fraction is 4/21

d) number of nickels: 8

therefore fraction is 8/21

4 0
3 years ago
The mean SAT score in mathematics, M, is 600. The standard deviation of these scores is 48. A special preparation course claims
kupik [55]

Answer:

Step-by-step explanation:

The mean SAT score is \mu=600, we are going to call it \mu since it's the "true" mean

The standard deviation (we are going to call it \sigma) is

\sigma=48

Next they draw a random sample of n=70 students, and they got a mean score (denoted by \bar x) of \bar x=613

The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.

- So the Null Hypothesis H_0:\bar x \geq \mu

- The alternative would be then the opposite H_0:\bar x < \mu

The test statistic for this type of test takes the form

t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.

With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

t=\frac{| \mu -\bar x |} {\sigma/\sqrt{n}}\\\\= \frac{| 600-613 |}{48/\sqrt(70}}\\\\= \frac{| 13 |}{48/8.367}\\\\= \frac{| 13 |}{5.737}\\\\=2.266\\

<h3>since 2.266>1.645 we  can reject the null hypothesis.</h3>
6 0
3 years ago
Read 2 more answers
Please help!
Vlada [557]

Option 3: 2^{\frac{5}{6}} is the right answer

Step-by-step explanation:

Given expression is:

(\sqrt{2})(\sqrt[3]{2} )

In order to simplify the expression we have to convert the radicals in exponents

2^{\frac{1}{2}} . 2^{\frac{1}{3}}

As he base is same, the powers can be added

=2^{\frac{3+2}{6}}\\=2^{\frac{5}{6}}

Hence,

Option 3: 2^{\frac{5}{6}} is the right answer

Keywords: Exponents, radicals

Learn more about exponents at:

  • brainly.com/question/4771355
  • brainly.com/question/4786449

#LearnwithBrainly

6 0
3 years ago
You run 4and3/4 miles through a park each day if you ran that distance five times last week how many miles did you run
zzz [600]
23.75 miles, because you would take 4 and 3/4 (4.75) and multiply by 5 :)
7 0
3 years ago
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