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3 years ago

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can this problem be solved using the unitary method?yes or no.An oven has a maximum temperature of 220°c.what will it be in 2 da

ys time

1 answer:

iogann1982 [59]3 years ago

8 0

Answer:

yes 25 :)

I'm sorry if I'm wrong

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Need some math help thanks in advance!

vredina [299]

Answer:

x = 10

y = 6

Step-by-step explanation:

<u>Vertical Angle Theorem</u>: When two straight lines intersect, the opposite vertical angles are always equal to each other.

⇒ m∠1 = m∠3 and m∠2 = m∠4

⇒ m∠1 = m∠3

⇒ 10x = 100

⇒ x = 10

<u>Linear pair:</u> Two adjacent angles which sum to 180°.

⇒ m∠1 + m∠2 = 180°

⇒ m∠3 + m∠4 = 180°

⇒ 100 + 10y + 20 = 180

⇒ 120 + 10y = 180

⇒ 10y = 60

⇒ y = 6

7 0

2 years ago

Solve the inequality showing all steps needed to justify your answer. State your solution in interval notation

dybincka [34]

<span>Which two measures did the United States take to counter terrorism after the September 11 attacks?

</span>

5 0

3 years ago

Need help on this problems!

Fofino [41]

For six you can write 1/4 because there is 4 pennies and 1 represents each penny

for number 5 you can put 2/10 because there is 10 coins and 2 quarters

and for number 7 is that Bradley has 10 coins not 9 so it would be 1/10

3 0

3 years ago

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BabaBlast [244]

$\underline{\bf{Given \:equation:-}}$

$\\ \sf{:}\dashrightarrow ax^2+by+c=0$

$\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.$

$\sf We\:know,$

$\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}$

$\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}$

$\underline{\large{\bf Identities\:used:-}}$

$\boxed{\sf (a+b)^2=a^2+2ab+b^2}$

$\boxed{\sf (√a)^2=a}$

$\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}$

$\boxed{\sf \sqrt{\sqrt{a}}=a}$

$\underline{\bf Final\: Solution:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}$

$\bull\sf Apply\: Squares$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}$

$\bull\sf Put\:values$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}$

$\bull\sf Simplify$

$\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}$

$\underline{\bf More\: simplification:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}$

$\underline{\Large{\bf Simplified\: Answer:-}}$

$\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}$

5 0

2 years ago

Read 2 more answers

Put the fractions in order smallest to largest<br> 7/10, 2/3 , 4/5, 11/15

Brrunno [24]

Answer:

Step-by-step explanation:

2/3, 7/10, 11/15, 4/5

8 0

3 years ago