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Viktor [21]
3 years ago
12

Graph the line y-2=3/10(x-6)

Mathematics
1 answer:
fenix001 [56]3 years ago
3 0

Answer:fbrhthtjthth

Step-by-step explanation:

Nrntntngmtn

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Simplify x = cos[2 arcsin(3/5)].<br><br> -7/25<br> 7/25<br> 4/5
Marina CMI [18]

Answer:

7/25

Step-by-step explanation:

Let \theta= \arcsin(\frac{3}{5}) so we have x=\cos(2\theta)

As \cos(2\theta)=\cos^2\theta-\sin^2\theta, we'll have \cos[2\arcsin(\frac{3}{5})]=\bigr[\cos(\arcsin(\frac{3}{5}))\bigr]^2-\bigr[(\sin(\arcsin(\frac{3}{5}))\bigr]^2

To determine \cos(\arcsin(\frac{3}{5})), construct a right triangle with an opposite side of 3 and a hypotenuse of 5. This is because since \theta=\arcsin(\frac{3}{5}), then \sin\theta=\frac{3}{5}=\frac{\text{Opposite}}{\text{Hypotenuse}}. If you recognize the Pythagorean Triple 3-4-5, you can figure out that the adjacent side is 4, and thus, \cos\theta=\frac{4}{5}=\frac{\text{Adjacent}}{\text{Hypotenuse}}. This means that \cos(\arcsin(\frac{3}{5}))=\frac{4}{5}.

Hence, \cos[2\arcsin(\frac{3}{5})]=(\frac{4}{5})^2-(\frac{3}{5})^2=\frac{16}{25}-\frac{9}{25}=\frac{7}{25}

5 0
2 years ago
Can someone help me with this quickly pleaseee
Sati [7]

Answer:

≈ 52m^2

Step-by-step explanation:

1)the face of a semicircle: (\pi*r^2)/2

2)the face of a rectangle: 6*5

3)the face of a triangle: (3*5)/2

1)  d=6m r=3m  (3.14*3^2)/2=28.26/2=14.13

2)  6*5=30

3)  (3*5)/2=15/2=7,5

Full surface:  14.13+30+7.5=51.63

answer:  51.63m^2 ≈ 52m^2

7 0
2 years ago
Read 2 more answers
Find 3 different possibile pairs of values for a and b ​
Lynna [10]

a=1, b =18

a=2, b = 9

a = 3 , b = 6

3 0
3 years ago
Read 2 more answers
Easy pllsssssss help
viktelen [127]

Answer:

87.5(the first one)

Step-by-step explanation:

first simplify 4 to the 5th power(20) and multiply by 4 to the -7th(-35) and you will get -700 divide that by 4 to the -2nd(-8) and you will get 87.5

6 0
3 years ago
Read 2 more answers
Determine the values of x when f(x)=40 for the function f(x)=2(x-3)^2-8
SpyIntel [72]

Answer:

x = 3 ± \sqrt{24}

or

x = 3 + \sqrt{24}, x = 3 - \sqrt{24}

Step-by-step explanation:

given f(x) = 2(x - 3)^2 - 8, find when f(x) = 40

So, we plug in 40 for f(x) in the 1st equation and solve for x.  (Aim to got x on its own)

40 = 2 (x - 3)^2 - 8

+ 8          + 8

-----------------------------

48 = 2 (x - 3)^2

/2            /2

-----------------------------

24 = (x - 3)^2

square root both sides

--------------------

\sqrt{24} = x - 3

x = 3 ± \sqrt{24}

5 0
2 years ago
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