The wire is attached 155 feet off the ground.sine(27) = 155 / hypotenuse hypotenuse = 155 / sine (27)hypotenuse =155 / 0.45399hypotenuse =
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341.42 </span></span></span>This means the guy wire is 341.42 feet long.
<span>Let the major axis = 2a , and the minor axis = 2b ∴ a = 26/2 = 13 and b = 24/2 = 12 and the equation of foci: c² = a² - b² = 13² - 12² = 169 - 144 = 25 ∴ c = √25 = 5
∴ The distance between the foci = 2 * 5 = 10 </span>
