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3 years ago

Find the perimeter and area of this circle plz. due today.

Mathematics

2 answers:

miv72 [106K]3 years ago

7 0

The circumference or perimeter of the circle is 94.25 ft
The area of the circle is 706.86 ft

Alik [6]3 years ago

5 0

If the diameter is 30 ft then the area of the circle is 706.5 you can approximate it if you want and you will have 707.

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if there are 12 dogs that sell for $104 and 8 cats that sell for $25. At the end of the day there are 4 dogs left and 5 cats lef

Vinil7 [7]

Initially there were 12 dogs

dogs left at the end of day =4

number of dogs sold=12-4=8

price of one dog=$104

price of 8 dogs = 104*8= $832

initially there were 8 cats

cats left at the end of day =5

number of cats sold =8-5=3

price of one cat= $25

price of 3 cats =25*3= $75

ratio of sales for dogs to cats = 832/75

7 0

3 years ago

Solve the system with<br> elimination.<br> x - y = 10<br> 3x - 2y = 25

raketka [301]

Answer:

Step-by-step explanation:

{x,y}={5,-5}

8 0

2 years ago

Please help ill give you brainliest

SVEN [57.7K]

The first one is 154

The second one is 12.65^2

3 0

3 years ago

Presley is organizing the school book sale. Each stall will have 40 books on the shelf and 2 boxes of books with b books inside.

Anit [1.1K]

40s+2bs+200=number of books needed

if we want 12 books and 8 stalls

b=12
s=8
solve

40(8)+2(12)(8)+200=
320+192+200=
712

needs 712 books

7 0

3 years ago

Read 2 more answers

Solve 5x^2 - 7x + 2 = 0 by completing the square.

Reika [66]

Answer: The correct option is (c) $\dfrac{49}{100}.$

Step-by-step explanation: We are given to solve the following quadratic equation by the method of completing the square:

$5x^2-7x+2=0~~~~~~~~~~~~~~~~~~~(i)$

Also, we are to find the constant added on both sides to form the perfect square trinomial.

We have from equation (i) that

$5x^2-7x+2=0\\\\\Rightarrow x^2-\dfrac{7}{5}x+\dfrac{2}{5}=0\\\\\\\Rightarrow x^2-2\times x\times \dfrac{7}{10}+\left(\dfrac{7}{10}\right)^2+\dfrac{2}{5}=\left(\dfrac{7}{10}\right)^2\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49}{100}-\dfrac{2}{5}\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{49-40}{100}\\\\\\\Rightarrow \left(x-\dfrac{7}{10}\right)^2=\dfrac{9}{100}\\\\\\\Rightarrow x-\dfrac{7}{10}=\pm\dfrac{3}{10}\\\\\\\Rightarrow x=\pm\dfrac{3}{10}+\dfrac{7}{10}.$

So,

$x=\dfrac{3}{10}+\dfrac{7}{10},~~~~~~~~x=-\dfrac{3}{10}+\dfrac{7}{10}\\\\\\\Rightarrow x=\dfrac{10}{10},~~~~~~~~\Rightarrow x=\dfrac{-3+7}{10}\\\\\\\Rightarrow x=1,~-\dfrac{2}{5}.$

Thus, the required solution is $x=1,~-\dfrac{2}{5}.$ and the value of the constant added is $\dfrac{49}{100}.$

Option (c) is correct.

3 0

3 years ago