What is the simplified form of i ^32?
A. -i
B. 1
C. i
D. -1
2 answers:
Answer:
1
Step-by-step explanation:
The pattern of imaginary numbers taken to exponents goes as thus:
i^1= i
i^2= -1
i^3= -i
i^4= 1
To solve this problem, divide the exponent by 4:
32/4= <u>8 </u>
Now rewrite i^32 as (i^4)^8
<em>(When exponents are raised by an exponent you multiply them together)</em>
i^4=1, this is your answer
divide exponent by 4
since the remainder is zero, the equation can be rewritten as i^0 and any number to the 0 power is 1
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