All categories

3 years ago

What is the simplified form of i ^32? A. -i B. 1 C. i D. -1

Mathematics

2 answers:

Serga [27]3 years ago

6 0

Answer:

Step-by-step explanation:

The pattern of imaginary numbers taken to exponents goes as thus:

i^1= i

i^2= -1

i^3= -i

i^4= 1

To solve this problem, divide the exponent by 4:

32/4= 8

Now rewrite i^32 as (i^4)^8

(When exponents are raised by an exponent you multiply them together)

i^4=1, this is your answer

ElenaW [278]3 years ago

5 0

divide exponent by 4

since the remainder is zero, the equation can be rewritten as i^0 and any number to the 0 power is 1

You might be interested in

Solve for m: 8(m + 2) = 3(12 - 4m)

Tema [17]

Answer:

m=1

Step-by-step explanation:

step 1: 8(m + 2) = 3(12 - 4m) remove the parentheses

step 2: 8 m + 2 = 3 12 - 4m move the terms

step 3: 8m+ 12m= 36 - 16 collect like terms and calulate

step 4: 20m=20 divide both sides

solution: m=1

3 0

3 years ago

Read 2 more answers

Combine like terms to simplify the expression: 2/5k-3/5+1/10k

charle [14.2K]

Answer:

1/2k-3/5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

BRAINLIEST ANSWER Twice the difference of a number and 4 is equal to three times the sum of the number and 6. Find the number.

Lubov Fominskaja [6]

Answer: -26

Step-by-step explanation:

2(n - 4)= 3(n + 6)

2n -8 = 3n + 18

+8 +8

2n = 3n + 26

-3 -3

-1n = 26

n= -26

8 0

3 years ago

Solve for y, where v is a real number. Vu+ 7 = 8

Blababa [14]

V is a real number Because v is 1 which will tell you you came from 7 to 8 which was a 1 jump .

8 0

3 years ago

Read 2 more answers

Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a king and

STALIN [3.7K]

Answer:

0.0181 probability of choosing a king and then, without replacement, a face card.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability of choosing a king:

There are four kings on a standard deck of 52 cards, so:

$P(A) = \frac{4}{52} = \frac{1}{13}$

Probability of choosing a face card, considering the previous card was a king.

12 face cards out of 51. So

$P(B|A) = \frac{12}{51}$

What is the probability of choosing a king and then, without replacement, a face card?

$P(A \cap B) = P(A)P(B|A) = \frac{1}{13} \times \frac{12}{51} = \frac{1*12}{13*51} = 0.0181$

0.0181 probability of choosing a king and then, without replacement, a face card.

5 0

3 years ago