We are given that
Max's grade on the first math exam was a 94
so, first exam grade =94
His grade on his seond math exam was an 89
so, second exam grade =89
change in grade=(first exam grade)-(second exam grade)
change in grade=94-89
change in grade=5
Percentage = ( change in grade)/( first exam grade) *100
so, percentage is
so,
the percent of change in Max's grade to the nearest whole percentage was 5%..........Answer
Answer:
see explanation
Step-by-step explanation:
Given that M is directly proportional to r³ then the equation relating them is
M = kr³ ← k is the constant of proportion
To find k use the condition when r = 4, M = 160, thus
160 = k × 4³ = 64k ( divide both sides by 64 )
2.5 = k
M = 2.5r³ ← equation of variation
(a)
When r = 2, then
M = 2.5 × 2³ = 2.5 × 8 = 20
(b)
When M = 540, then
540 = 2.5r³ ( divide both sides by 2.5 )_
216 = r³ ( take the cube root of both sides )
r = = 6