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olga_2 [115]
3 years ago
14

Why are probability and statistics important?

Mathematics
1 answer:
Anestetic [448]3 years ago
7 0

Answer:

Studying probability and statistics will allow you to see the world from an entirely different perspective, since the subjects will give you the tools to model and analyze situations, which involve uncertainty.

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Y is a differentiable function of x. Choose the alternative that is the derivative dy / dx.
murzikaleks [220]

Differentiating both sides of

x^3-y^3=1

with respect to <em>x</em> yields (using the chain rule)

3x^2 - 3y^2 \dfrac{\mathrm dy}{\mathrm dx} = 0

Solve for d<em>y</em>/d<em>x</em> :

3x^2 - 3y^2 \dfrac{\mathrm dy}{\mathrm dx} = 0 \\\\ 3y^2\dfrac{\mathrm dy}{\mathrm dx} = 3x^2 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \dfrac{3x^2}{3y^2} = \dfrac{x^2}{y^2}

The answer is then D.

3 0
2 years ago
What is the value of the correlation coefficient r of the data set?
vova2212 [387]

The correlation coefficient r of the data set is <em>-0.28</em>

7 0
3 years ago
Can you make all the numbers from 1 to 20 using 4 fours?
Effectus [21]

Answer: no you can't you can only use 5 numbers when going by 4's

Step-by-step explanation: 4, 8, 12, 16, 20

8 0
3 years ago
Read 2 more answers
300 ml of pure alcohol is poured from a bottle containing 2 l of pure alcohol. Then, 300 ml of water is added into the bottle. A
Ede4ka [16]

Answer:

The present percentage of pure alcohol in the solution is 72.25% of pure alcohol

Step-by-step explanation:

The volume of pure alcohol poured from the 2 l bottle of pure alcohol = 300 ml of pure alcohol

The volume of water added into the bottle after pouring out the pure alcohol = 300 ml of water

The volume of diluted alcohol poured out of the bottle = 300 ml of diluted alcohol

The volume of water added into the bottle of diluted alcohol after pouring out the 300 ml of diluted alcohol = 300 ml of water

Step 1

After pouring the 300 ml of pure alcohol and adding 300 ml of water to the bottle, the percentage concentration, C%₁ is given as follows;

C%₁ = (Volume of pure alcohol)/(Total volume of the solution) × 100

The volume of pure alcohol in the bottle = 2 l - 300 ml = 1,700 ml

The total volume of the solution = The volume of pure alcohol in the bottle +  The volume of water added = 1,700 ml + 300 ml = 2,000 ml = 2 l

∴ C%₁ = (1,700 ml)/(2,000 ml) × 100 = 85% percent alcohol

Step 2

After pouring out 300 ml diluted alcohol from the 2,000 ml, 85% alcohol and adding 300 ml of water, we have;

Volume of 85% alcohol = 2,000 ml - 300 ml = 1,700 ml

The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol = 85/100 × 1,700 = 1,445 ml

The total volume of the diluted solution = The volume of the 85% alcohol in the solution + The volume of water added

∴ The total volume of the twice diluted solution = 1,700 ml + 300 ml = 2,000 ml

The present percentage of pure alcohol in the solution, C%₂ = (The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol)/(The total volume of the diluted solution) × 100

∴ C%₂ = (1,445 ml)/(2,000 ml) × 100 = 72.25 %

The present percentage of pure alcohol in the solution, C%₂ = 72.25%

3 0
3 years ago
ANSWER ONLY IF U KNOW I RLLY NEED HELP THIS IS THE LAST OF MY POINTS.
Ostrovityanka [42]
Sure the answer is 2 4.5
7 0
3 years ago
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