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3 years ago

So I’m not smart so like help meh pleasee What is 49% of 200?

Mathematics

1 answer:

____ [38]3 years ago

3 0

Answer:98

Step-by-step explanation:

We assume, that the number 200 is 100%.if 200 is 100%, so we can write it down as 200=100%.We also know, that x is 49% of the output value, so we can write it down as x=49%.Now we have two simple equations:

1) 200=100%

2) x=49%

we multiply both sides of the equation by x.then we divide both sides of the equation.

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.75 (x +20)=2 +0.5 (x-2)

nalin [4]

Answer:

i need help too

Step-by-step explanation:

7 0

2 years ago

−10x+5=−6x−35 ooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo

Zarrin [17]

Answer:

x=10

Step-by-step explanation:

Add 6x to both sides.

−4x+5=−35

Subtract 5 from both sides.

−4x=−40

Divide both sides by -4.

$\frac{-4x}{-4}=\frac{-40}{-4}$

x=10

hope this helps

8 0

3 years ago

Read 2 more answers

7m2 + 3m + 4m2<br> What is the answer to this

mylen [45]

I’m assuming the 2’s are supposed to be exponents so you’re gonna to combine 7m^2 and 4m^2 to get 11m^2 so you’re answer would be

11m2+3m

You dint know the value of M so you can’t solve it, especially because there’s no equal sign with a number or expression/equation after it.

8 0

2 years ago

manuel deposits $10000 for 12 yr in an account paying 4% compounded annually.He then puts this total amount on deposit in anothe

Naddik [55]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$10000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &12
\end{cases}
\\\\\\
A=10000\left(1+\frac{0.04}{1}\right)^{1\cdot 12}\implies A=1000(1.04)^{12}\\\\\\ A\approx 16010.32$

he then turns around and grabs that money and sticks it for another 9 years,

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
~~
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$16010.32\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2\\
t=years\to &9
\end{cases}
\\\\\\
A=16010.32\left(1+\frac{0.05}{2}\right)^{2\cdot 9}\implies A=16010.32(1.025)^{18}
\\\\\\
A\approx 24970.64$

add both amounts, and that's how much is for the whole 21 years.

6 0

3 years ago

Answer please I’m dying from math

vovikov84 [41]

Step-by-step explanation:

It's C

I hope it helped:)

8 0

2 years ago