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kupik [55]
3 years ago
13

The sum of 2 numbers is 50. the second number is 5 times the first. what is the number.

Mathematics
2 answers:
grandymaker [24]3 years ago
7 0
Let the first number be x, and the second 5x. The second is five times the first, so thats why it is 5x. Now, add x+5x=50. Simplify the equation to be 6x=50, because x+5x is 6x. Do the opposite of multiplyig because 6x is the same as 6 times x. Divide 6 on both sides. 50 divided by six is your first number (x). Now multiply your quotient by 5 to find the second number, and those are your two numbers.
sp2606 [1]3 years ago
3 0

Let the first and smaller number be x. Since the second number is 5 times the first, the second number is 5x. We also know both of these numbers must add to 50; thus, we can create the following equation.

x+5x=50

Combine like terms

6x = 50

Divide both sides by 6

x = 50/6 = 25/3 \approx 8.333

This is the value of the first number. The number you're looking for isn't specified in the question description, so I'll just provide the value of the second number. The second number has to be 5 times the first.

Thus, we just multiply 5 to x.

5x = 5(25/3) = 125/3 \approx 41.667

That's the value of the second number.

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3 years ago
28% of what number is 63
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We set up a proportion: 63/?= 28/100

Cross multiply: 28*?= 63*100
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Zanzabum
<h3>Answer:   0.5</h3>

This is equivalent to the fraction 1/2

==============================================================

Explanation:

The distance from A to B is 3 units. We can count out the spaces, or subtract the x coordinates of the two points and apply absolute value.

|A-B| = |-5-(-8)| = |-5+8| = |3| = 3

or

|B-A| = |-8-(-5)| = |-8+5| = |-3| = 3

We can say that segment AB is 3 units long.

--------------------------

The distance from A' to B' is 1.5 units because...

|A'-B'| = |-2.5-(-4)| = |-2.5+4| = |1.5| = 1.5

or

|B'-A'| = |-4-(-2.5)| = |-4+2.5| = |-1.5| = 1.5

The absolute values ensure the distance is never negative.

We can say A'B' = 1.5

---------------------------

Now divide the lengths of A'B' over AB to get the scale factor k

k = (A'B')/(AB)

k = (1.5)/(3)

k = 0.5

0.5 converts to the fraction 1/2.

The smaller rectangle A'B'C'D' has side lengths that are exactly 1/2 as long compared to the side lengths of ABCD.

3 0
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