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Ratling [72]
3 years ago
17

Which board geometrically represents 4x2 – 1 using algebra tiles? An algebra tile configuration showing only the product spot, w

hich has 9 tiles in 3 columns with 3 rows. First row: 2 + x squared, 1 + x. Second row: 2 + x squared, 1 + x. Third row: 2 negative x, 1 +. An algebra tile configuration showing only the product spot, which has 9 tiles in 3 columns with 3 rows. First row: 2 + x squared, 1 + x. Second row: 2 + x squared, 1 + x. Third row: 2 negative x, 1 negative. An algebra tile configuration showing only the product spot, which has 9 tiles in 3 columns with 3 rows. First row: 2 + x squared, 1 negative x. Second row: 2 + x squared, 1 negative x. Third row: 2 negative x, 1 +. An algebra tile configuration showing only the product spot, which has 9 tiles in 3 columns with 3 rows. First row: 2 + x squared, 1 + x. Second row: 2 + x squared, 1 + x. Third row: 2 + x, 1 +.
Mathematics
2 answers:
Lady bird [3.3K]3 years ago
9 0

Answer: it’s the second one

Step-by-step explanation:

svp [43]3 years ago
8 0

Answer:

B is the answer

Step-by-step explanation:

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The Megasoft company gives each of its employees the title of programmer (P) or project manager (M). In any given year 70% of pr
Ne4ueva [31]

Answer:

it will take a programmer about 16.67 times to work before they are fired

Step-by-step explanation:

From the information given;

The transistion matrix for this study can be computed as:

       P          M         X

P     0.7      0.2        0.1

M     0        0.95     0.05

X      0        0            1

where;

The probability that the programmer remains a programmer = (P *P)

The probability that the programmer turns out to be a manager = (P*M)

The probability that the programmer is being fired = (P*X)

Thus, the required number of years prior to the moment being fired for an employee y(P), for programmer and y(M) for manager is represented by ;

y(P)=1+0.7y(P)+0.2y(M)

y(M)=1+ 0.95y(M).

0.05y(M)=1

y(M) = \dfrac{1}{0.05}

y(M) =20

y(P)=1+0.7y(P)+0.2y(M)

y(P) - 0.7y(P) = 1 + 0.2y(M)

0.3y(P) = 1 + 0.2(20)=1+4

0.3y(P) = 1 + 4

0.3y(P) =  5

y(P)=\dfrac{5}{0.3}

y(P)=16.67

Therefore, it will take a programmer about 16.67 times to work before they are fired

8 0
3 years ago
Find each missing length to the nearest tenth. (Using Pythagorean Theorem)​
irinina [24]

Answer:

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Step-by-step explanation:

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4 years ago
Does anyone know the quitent of 83/4
igomit [66]

Answer:

20.75

Step-by-step explanation:

The quotient of 83/4 is 20.75

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If the geometric series 54+36+...+128/27 has seven terms in it's sum then the value of the sum is...
Scorpion4ik [409]
I would say 4 but you might want to check again
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3 years ago
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