Try this option:
1. if 8*x²+b*x+3=8*x²+p*x+q*x+3, then ⇒ b=p+q.
2. p*q = max_value (b²/2), if p=q=0.5*b, and p*q→-oo, if p>0 and q<0 or p>0 q<0.
3. example:
given 8x²+10x+3, the student rewrites it as a) 8x²+5x+5x+3 (5*5=25-max value); b) 8x²+0.01x+9.99x+3 (9.99*0.01=0.0999→0); c) 8x²-20x+30x+3 (p*q=-600).
answer: (-oo;0.5b²)
Answer:
17 m
Step-by-step explanation:
As shown in the figure, 
is the ground level, 
is the old level of water which was at 20 m below ground level, 
is the new level of water which is 5m above of old level. The height of wall of the well, 1.20 m, and the the pelly at 80 cm =0.80 m, has been shown too.
The minimum length of the rope is equal to the distance between the pully and the new water level, indicated by the length 
in the figure.
So, 
Hence, Raghu must use a rope having the minimum length 17 m to draw water from the well.
The quotient is<em> 197</em> .
You have a choice of 3 tools to use, any one of which will return the same answer:
-- your calculator
-- your pencil
-- your brain
Answer:
Step-by-step Solution:
Simply change the denominators such that both denominators are the same. Then, add the fractions to get your result.
- 1/2 + 1/6
- => 3 x 1/2 x 3 + 1/6
- => 3/6 + 1/6
- => 4/6 = 2/3
Hence, the solution is 2/3.
Answer:
In 2 2/15 hours, the prices will be same
Step-by-step explanation:
I hope this helps :)
