ANSWER:
Let t = logtan[x/2]
⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx
⇒dt = 1/2 cos² x/2 × cot x/2dx
⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx
⇒dt = 1/2 cosx/2 / sin x/2 dx
⇒dt = 1/sinxdx
⇒dt = cosecxdx
Putting it in the integration we get,
∫cosecx / log tan(x/2)dx
= ∫dt/t
= log∣t∣+c
= log∣logtan x/2∣+c where t = logtan x/2
Answer:
(-4, -8)
Step-by-step explanation:
Use the substitution method. x = -4, so y = (1/2)x - 6 becomes:
y = (1/2)(-4) - 6, or y = -2 - 6, or y = -8.
The solution is (-4, -8).
Answer:
68/9
Step-by-step explanation:
34 ÷ (14 − 5) × 2
PEMDAS
Parentheses first
34 ÷ (9) × 2
We have no Exponents so
Multiply and Divide from left to right
34/9 *2
68/9
Begin
3x-4=14
3x=18
x=6
.5n=1.25
n=2.5
x+1=2x-2
x+3=2x
3=x
x+3=10
x=7
6x-13=-11
6x=2
x=1/3
p=4-p
2p=4
p=2
End
