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Kazeer [188]
3 years ago
5

Help please!!!!!!!!!!!!!!

Mathematics
2 answers:
Crank3 years ago
8 0

eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

mojhsa [17]3 years ago
4 0

Answer:

it is def and close to what you get and you get

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What is the standard form of y=6(x-3)²-2​
aleksandrvk [35]

Answer:

B

Step-by-step explanation:

y = 6(x^2-6x+9)-2

y = 6x^2-36x+54-2

y = 6x^2-36x+52

7 0
4 years ago
Craig collects stamps he collected a total of 150 stamps if 88% of the stamps be collected were foreign how many stamps did he c
sertanlavr [38]

Answer:

18 Non Foreign Stamps

Step-by-step explanation:

Given data

Total stamps= 150

Foreign Stamps= 88% of the total stamps

Hence the number of foreign stamps is

=88/100*150

=0.88*150

=132 Foreign Stamps

The number of stamps that is Non Foreign Stamps is

=150-132

=18 Non Foreign Stamps

8 0
3 years ago
Brainly gives me so many trust issues, especially when 2 people told you the same answer and you get it wrong GJKEGHG
Fiesta28 [93]

Answer:

facts

Step-by-step explanation:

:)

8 0
3 years ago
Read 2 more answers
2y +3&lt;11<br> What is the largest value of y could be?
Evgesh-ka [11]
The greatest value of y is 2y+3=11 => y=4
5 0
3 years ago
Read 2 more answers
Find so that the distance between (−2,3) and (,1) is √13
belka [17]

The distance between (-2, 3) and (-5, 1) is √13.

or, the distance between (-2, 3) and (1, 1) is √13.

We know that the length of the line segment connecting any two points represents the distance between them. There is just one line that connects the two points. Therefore, by measuring the length of the line segment that connects the two points, the distance between them can be determined. If (a, b) and (c, d) be two points, then the distance between them is \sqrt[]{(b - a)^{2} +(d- c)^{2} }.

Here, one point is (-2, 3).

Let the other point be (x, 1).

Given that the distance is √13.

Now, \sqrt[]{(x - (-2))^{2} +(1 - 3)^{2} } = \sqrt{13}  

i.e. \sqrt[]{(x + 2)^{2} +( - 2)^{2} } =\sqrt{13}

i.e. \sqrt[]{x^{2}+4x +4 +4 }=\sqrt{13}

i.e. x^{2}+4x +8 =13

i.e. x^{2}+4x + 8- 13=0

i.e.x^{2}+4x -5=0

i.e. x^{2} +5x - x -5=0

i.e. x(x+5)-1(x+5)=0

i.e. (x+5)(x-1)=0

i.e. x=-5,1

So, the point is either (-5, 1) or (1, 1).

Therefore, the required point is either (-5, 1) or (1, 1).

i.e. the distance between (-2, 3) and (-5, 1) is √13.

or, the distance between (-2, 3) and (1, 1) is √13.

Learn more about distance here -

brainly.com/question/431605

#SPJ10

7 0
2 years ago
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