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tia_tia [17]
3 years ago
15

What are the factors of 54

Mathematics
1 answer:
larisa [96]3 years ago
3 0

Answer:

1, 2, 3, 6, 9, 18, 27, 54

Step-by-step explanation:

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the length of a rectangle is 6 meters less than twice the width. The area of the rectangle is 140m². Find the dimensions of the
AveGali [126]

Answer:

Here's what we know:

A = Lw (Area is length times width)

L = 2w + 6 (length is twice the width plus 6)

A = 140 (Area is 140 m2)

Plug in the variable values:

140 = w(2w + 6)

Distribute:

140 = 2w2 + 6w

Subtract 140:

2w2 + 6w - 140 = 0

Factor out a 2:

2(w2 + 3w - 70) = 0

Divide both sides by 2:

w2 + 3w - 70 = 0

(w + m)(w - n)

When we factor out the quadratic, we know it's going to be a +/- situation because the c value in the quadratic is negative, and the two numbers are going to be three away, the plus next to the 3 meaning that the larger number is going to be positive:

(w + 10)(w - 7) = 0

w = -10, 7

We can't have a negative length, so we can toss out the -10, leaving us with w = 7 meters.

L = 2 * 7 + 6

L = 14 + 6

L = 20

Check:

140 = 20 * 7

140 = 140

8 0
2 years ago
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If f(x) = (x - 1) / (x + 2), then the range of f is given by the interval
Veseljchak [2.6K]

Answer:

B and D

Step-by-step explanation:

Have a great day!

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3 0
3 years ago
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7z2 5z4 d3 d8<br> I don't know how you are supposed to do it?
Serga [27]

Answer:

35 {z}^{6} {d}^{11}

Step-by-step explanation:

Assuming you are supposed to simplify:

7 {z}^{2}  \times 5 {z}^{4}  \times  {d}^{3}  \times  {d}^{8}

Then we need to apply the product rule of indices.

{a}^{m}  \times  {a}^{n}  =  {a}^{m + n}

So we multiply to get:

35 {z}^{2 + 4}  \times  {d}^{3 + 8}

We now simplify the exponents to get:

35 {z}^{6}  \times  {d}^{11}

Therefore the required product is

35 {z}^{6} {d}^{11}

3 0
3 years ago
What is the answer to this question ? (1.5×107)⋅30,000⋅(6.7×105)
Kipish [7]
The answer is 3.387352e9
6 0
2 years ago
PLS HELP ASAP ILL GIVE BRAINLKEST THANKS
Arisa [49]

Answer:

(4,4)

Step-by-step explanation:

hope this help

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2 years ago
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