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3 years ago

What is y and x intercept of 3x-2y=12

2 answers:

8 0

These intercepts are plotted in Figure 3.1 and the line 3x + 2y = 12 is drawn through them. Figure 3.2: Adding the graph of y = x + 1. The second equation y = x+ 1 has slope-intercept form y = mx + b. Hence, the slope is m = 1 and the y-intercept is (0, 1).

Mrac [35]3 years ago

5 0

First, put the equation in standard form for the equation of a line which is y = mx + b where m is the slope and b is the y-intercept:

3x - 2y = 12

-2y = -3x + 12

y = 3/2x - 6

We plug in 0 for x to find the y-intercept:

y = 3/2(0) - 6

y = -6

Now we can see the the y-intercept must be (0, -6).

Now to find the x intercept, plug in 0 for y:

0 = 3/2x - 6

3/2x = 6

x = 4

So the x intercept is (4, 0).

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2 years ago

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Y_Kistochka [10]

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3 years ago

Read 2 more answers

8^x=2^6 What is the value of x?

Anon25 [30]

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3 years ago

Tickets to a school basketball game cost $4 for students and $7 for adults. At the end of the night, 168 tickets are sold for a

stepan [7]

4s+7a=861
s+a=168

This can be solved using either elimination or substitution. I am going to use substitution.

Solve s+a=168 for s
s=168-a

Replace 168-a for s in 4s+7a=861
4(168-a)+7a=861
672-4a+7a=861

Solve for a
672+3a=861
3a=189
a=63

Substitute 63 for a in s=168-a
s=168-63=105

So, s=105 student tickets and a=63 adult tickets

3 0

3 years ago

Your 3 nieces and 3 nephews (6 children total) are visiting for the holidays. You must give them each a present. They all love l

marusya05 [52]

Answer:

The 6 Lego kits can be selected from the 9 available Lego kits in 84 ways.

Step-by-step explanation:

Use combinations to solve this problem.

Combination is defined as the selection of r elements from n distinct objects irrespective of the order. The objects cannot be replaced.

There are 9 Lego kits available.

And the total number of children is 6.

That is, we need to select 6 Lego kits from the 9 available Lego kits.

6 Lego kits can be selected from the 9 available Lego kits in $9\choose 6$ ways.

Solving the combination as follows:

${9\choose 6}=\frac{9!}{6!\times(9-6)!} \\=\frac{362880}{720\times6}\\ =84$

Thus, there are 84 ways to select 6 Lego kits from 9 available Lego kits.

4 0

2 years ago