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3 years ago

I need help asap. Its due i 10 min

Mathematics

2 answers:

Illusion [34]3 years ago

7 0

Answer:

John is correct because if the amount in a pack is 12 and there are 7 people if you do 12 divided by 7 you would know how much each can costs

Step-by-step explanation:

Hope this helps

Have a great day!

Iteru [2.4K]3 years ago

3 0

Answer:

Susan is correct because to get the total cost, we multiply the unit price by the number of people attending.

Step-by-step explanation:

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A number picked at random from the numbers 1 through 15 is prime. This "question" is on my study guide for Unit 6 Probability an

Sphinxa [80]

Solution:

we are given that

A number picked at random from the numbers 1 through 15 is prime.

As we know the number between 1 and 15 which are primes are listed below

2,3,5,7,11,13.

Here total number of favourable outcomes are 6.

The numbers 1 through 15 are as below:

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15.

Here total number of possible outcoes are 15.

Hence the probability that if a number picked at random from the numbers 1 through 15 is prime $=\frac{6}{15}=\frac{2}{5}=0.40$

Hence the probability that if a number picked at random from the numbers 1 through 15 is prime is 0.4

6 0

3 years ago

Read 2 more answers

Michael added 15 fish to his pond over a period of 5 days he added the same number of fish each day what was the change in the n

Yuri [45]

Answer:

Step-by-step explanation:

15 fish / 5 days = 3 fish per day

5 0

3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- see attachment for the generated data

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

Can someone Solve this math problem for me I'm having some trouble. 27×26+98÷25?

AlladinOne [14]

Answer:

705.92

Step-by-step explanation:

hope it's help

#MASTER GROUP

# FIRST MASTER

# PHILIPPINES

5 0

3 years ago

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Jackson played a video game for 1/6 hour. Bailey played a video game for 1/3 hour. Who played the video game for greater amount

Oksana_A [137]

Answer:

Bailey played longer.

Step-by-step explanation:

1/3 of an hour would be 20 minutes. 1/6 of an hour is 10 minutes.

6 0

3 years ago