The quadratic formula is -b + or - the square root of b squared - 4 times the a value and c value over 2a. So the roots would be -1.354249 and -6.645751. I believe these are the roots.
<span>The line goes through the points (4,-3) and (0,-2), so its gradient is (-2-(-3))/(0-4) = -1/4. The y-intercept is -2 because f(0)=-2. So the equation of the line is y = -1/4 x - 2.This can be represented by the linear function f(x) = (-1/4)x - 2.
The composite function ff is given by ff(x) = f(-1/4 x - 2) = (-1/4)((-1/4)x - 2) - 2 = x/16 - 3/2.</span>
To get the difference between the two diameters, all you have to do is subtract the smaller diameter (Mercury) from the larger diameter (Saturn) as follows:
Difference between the two diameters =diameter of Saturn-diameter of Mercury
Difference between the two diameters = (1.2*10^5) - (4.9*10^3)
Difference between the two diameters = 115100 km
Answer:
Step-by-step explanation:
The position of an object moving horizontally after t seconds is given by the function
s = 3t - t³
a) The object is stationary when there is no external force acting on the body. When the body is at rest, the body remains in a position and here is no distance covered by the object i.e s = 0
b) velocity is the change in displacement of a body with respect to time.
v = ds/dt
S = 3t - t³
V = ds/dt = 3-3t²
at t = 2
Velocity = 3-3(2)²
Velocity = 3-12
Velocity = -9m/s
c) acceleration is the change in velocity of a body with respect to time.
acceleration = dv/dt
If v = 3-3t²
a = dv/dt = -6t
When v = 0
0 = 3-3t²
-3 = -3t²
t² = 1
t = ±√1
t = 1sec
The acceleration of the object at v = 0 occurs at t = 1sec and -1sec
a = -6(1)
a = -6m/s²
d) Given the speed of the body v modelled by the function
v = 3-3t²
The speed is decreasing when it is less than zero as shown:
3-3t²< 0
3<3t²
1<t²
±1<t
1<t and -1<t
t>±1
t >1 and t>-1
The speed is decreasing when
3-3t²<0 and t>1 or t>-1
