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3 years ago

Perform the following calculation and express the answer in scientific

Mathematics

2 answers:

bekas [8.4K]3 years ago

8 0

Answer:

Hey there!

1.2 x 10^-2 times 3.0 x 10^-6 = 3.6 x 10^-8 m^2.

Hope this helps :)

zheka24 [161]3 years ago

8 0

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Pls help i cant find

MAXImum [283]

Answer:

Let's see the first two points: (-7, 5) and (-5, 9)

The line passes these points has a form of: y = Mx + b

=> 5 = (-7)M + b

9 = (-5)M + b

Subtract the 1st equation from 2nd equation, we have:

4 = 2M

=> M = 2

Substitute M back into 1st equation:

=> 5 = (-7)*2 + b

=> b = 19

=> y = 2x + 19

or y - 5 = 2x + 14

or y - 5 = 2(x + 7)

=> Option A is correct

Hope this helps!

5 0

3 years ago

Read 2 more answers

Find the value of x!!

Wewaii [24]

Answer:

x=23°

Step-by-step explanation:

93°+(3x+18)°=180°

93°+3x+18°=180°

111°+3x=180°

3x=180°-111°

3x=69°

x=69°:3

x=23°

3 0

3 years ago

Read 2 more answers

If you multiply 5(2x+3+4y), the answer is ______

Volgvan

Answer:

You don't even need to do the whole question. Just look at 5 times 2x. which is 10x then u get your answer

6 0

2 years ago

Read 2 more answers

Determine how many solutions if correct bainliest

PolarNik [594]

Answer:

No solutions

Step-by-step explanation:

6x+2y=20

-3x-y=-4 (by rewriting)

6/-3 = 2/-1≠20/-4

-2=-2≠-5

So it has no solutions

5 0

3 years ago

X = ? y = ? 16 45 degrees

mezya [45]

Let's put more details in the figure to better understand the problem:

Let's first recall the three main trigonometric functions:

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}$

For x, we will be using the Cosine Function:

$\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}$ $(16)Cosine(45^{\circ})\text{ = x}$ $(16)(\frac{1}{\sqrt[]{2}})\text{ = x}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = x}$

Therefore, x = 8√2.

For y, we will be using the Sine Function.

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}$ $\text{ (16)Sine }(45^{\circ})\text{ = y}$ $\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = y}$

Therefore, y = 8√2.

5 0

1 year ago