The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
Learn more about work done here:
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One way to carry out this problem is to simply take the value that you already know, which is that 1/5 is 20 % and multiply it by 2 for 2/5 or 2 (1/5ths) and do this for all of them. There is a pattern that occurs for every increase in one out of denominator of 5.
Answer:
1203.6 ---- the six is recurring ( .666666...)
Step-by-step explanation:
volume of hemisphere= 
x 3.14 x r^3
volume of cylinder= 3.14 x r^3 x h
1. Volume of hemisphere= 2/3 x 3.14 x 5^3 = 261.6 recurring
2. volume of cylinder = 3.14 x 5^2 x12 = 942
3. add the two together -----------> 1203.6
Answer:
1. is 45/2
2. is 12/5
3. is 4/5
4. is 14
5. is 28
6. is 6 hope this helps :)
Step-by-step explanation:
