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klemol [59]
3 years ago
9

What is 2 + 2 equal to

Mathematics
2 answers:
irga5000 [103]3 years ago
8 0
4....................?
Debora [2.8K]3 years ago
8 0
4 luvvvvvvvvvv 2+2 is 4 imagine having two apples and adding another two how much would you have? 4 luvvv!!!!!!! Xoxo
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The paper feed on a copying machine has room for a stack of paper 4.0 cm high. If 10 sheets of paper are 0.08 cm thick, how many
Ierofanga [76]
I don't know but I know it is going to be a lot
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3 years ago
What is the length of the major axis of the ellipse (x-7)^2/4+(y+3)^2/16=1
yuradex [85]
\bf \begin{array}{llll}
\cfrac{(x-{{ h}})^2}{{{ a}}^2}+\cfrac{(y-{{ k}})^2}{{{ b}}^2}=1\\\\ \cfrac{(x-{{ h}})^2}{{{ b}}^2}+\cfrac{(y-{{ k}})^2}{{{ a}}^2}=1
\end{array}\quad 
\begin{cases}
\textit{major axis}=a+a\\
a=\textit{the larger denominator}\\
b=\textit{smaller denominator}
\end{cases}\\\\
-----------------------------\\\\
\cfrac{(x-7)^2}{4}+\cfrac{(y+3)^2}{16}=1\implies \cfrac{(x-7)^2}{2^2}+\cfrac{(y+3)^2}{4^2}=1\quad 
\begin{cases}
a=4\\
b=2
\end{cases}
6 0
3 years ago
Solve for x. 144=8x<br><br> Please help
Anika [276]
The correct answer is x=18
7 0
3 years ago
Read 2 more answers
What is the surface area of a cylinder with the given dimensions?
mafiozo [28]

Step-by-step explanation:

 7^2 × 3.14 × 2 + 3.14×14×672×3.14×2+3.14×14×6 = 49 × 6.28 + 3.14 × 8449×6.28+3.14×84 = 307.72+263.76307.72+263.76 = 571.48 cm^2c

8 0
3 years ago
Please help with this calculus problem!
ELEN [110]
\dfrac{\mathrm dQ}{\mathrm dt}=\dfrac{a(1-5bt^2)}{(1+bt^2)^4}
Q(t)=\displaystyle\int\frac{a(1-5bt^2)}{(1+bt^2)^4}\,\mathrm dt

Let t=\dfrac1{\sqrt b}\tan u, so that \mathrm dt=\dfrac1{\sqrt b}\sec^2u\,\mathrm du. Then the integral becomes

\displaystyle\frac a{\sqrt b}\int\frac{1-5b\left(\frac1{\sqrt b}\tan u\right)^2}{\left(1+b\left(\frac1{\sqrtb}\tan u\right)^2\right)^4}\sec^2u\,\mathrm du
=\displaystyle\frac a{\sqrt b}\int\frac{1-5\tan^2u}{(1+\tan^2u)^4}\sec^2u\,\mathrm du
=\displaystyle\frac a{\sqrt b}\int\frac{1-5\tan^2u}{\sec^6u}\,\mathrm du
=\displaystyle\frac a{\sqrt b}\int(\cos^6u-5\sin^2u\cos^4u)\,\mathrm du
=\displaystyle\frac a{\sqrt b}\int(6\cos^2u-5)\cos^4u\,\mathrm du

One way to proceed from here is to use the power reduction formula for cosine:

\cos^{2n}x=\left(\dfrac{1+\cos2x}2\right)^n

You'll end up with

=\displaystyle\frac a{16\sqrt b}\int(5\cos2u+8\cos4u+3\cos6u)\,\mathrm du
=\displaystyle\frac a{16\sqrt b}\left(\frac52\sin2u+2\sin4u+\frac12\sin6u\right)+C
=\dfrac a{32\sqrt b}(5\sin2u+4\sin4u+\sin6u)+C
Q(t)=\dfrac{at}{(1+bt^2)^3}+C
6 0
3 years ago
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