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Oksana_A [137]
3 years ago
11

Elin’s old fish tank is leaking. Diagram not drawn to scale This old fish tank is in the shape of a cuboid. The base of this tan

k measures 60cm by 40cm. Before the leak, the height of the water level in Elin’s old fish tank was 45cm. Elin decides to replace her fish tank with a cylindrical one. 70 cm Diagram not drawn to scale 25 cm She selects a new cylindrical fish tank that has a radius of 25cm and a height of 70cm. Will all the original contents, including the water and the fish, fit into this cylindrical tank? You must show all your working.
Mathematics
1 answer:
ella [17]3 years ago
6 0

Step-by-step explanation:

nnsndnxnxndjenendjdnrjr

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Evaluate the following expression when x = 1/2 and y = -3.<br><br><br> -4xy
solong [7]

Answer:6

Step-by-step explanation:

-4xy

-4(1/2)(-3)

-4(-1.5)

6

3 0
2 years ago
Which of the following is equal to 5/8÷2/7?
natta225 [31]

Answer:

5/8 * 7/2

Step-by-step explanation:

Whenever you divide fractions, you can use the 'keep change flip' method.

You keep 5/8, change the division sign to multiplication, and then flip the second fraction.

1. 5/8 / 7/2  -  Keep 5/8

2. 5/8 * 7/2  -  Change division sign

3. 5/8 * 2/7  -  Flip the second fraction, 7/2 -> 2/7

5 0
3 years ago
Read 2 more answers
ZX bisects ∠WZY. If the measure of ∠YXZ is (6m – 12)°, what is the value of m?
Digiron [165]

Answer:

The correct answer is option B.  17

Step-by-step explanation:

It is given that, ZX bisects ∠WZY. If the measure of ∠YXZ is (6m – 12)°

To find the value of m

From the figure we can see that, triangle WYZ is an isosceles  triangle.

ZW = ZY

Then <YXZ = <WXZ = 90°

It is given ∠YXZ  = (6m – 12)°

(6m – 12)° =  90°

6m = 90 + 12  = 102

m = 102/6 = 17

Therefore the value of m = 17

The correct answer is option B.  17

8 0
2 years ago
Read 2 more answers
Special air bags are used to protect scientific equipment when a rover lands on the surface of Mars. On Earth, the function appr
PSYCHO15rus [73]

The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.

<h3>What is the approximation about?</h3>

From the question:

Mars: F(x) = 2/3\sqrt{64x}

Therefore, If x = 15

Then:

f (15) =  2/3 \sqrt[8]{15}

= 16/3\sqrt{15}

= 20.7ft/s

Hence, The nearest tenth of how fast a rover will hit Mars' surface after a bounce of 15 ft in height is 20.7ft/s.

Learn more about Estimation from

brainly.com/question/24592593

#SPJ1

8 0
1 year ago
Help me with problem
DENIUS [597]

Answer:

x = 16.67

Step-by-step explanation:

4x - 6 + 8x - 6 = 180

12x - 14 = 180

    + 14      + 14

12x = 194

/ 12    / 12

x = 16.67

4 0
2 years ago
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