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kozerog [31]
3 years ago
8

SOLVE PLEASE THANKSS The perimeter of a rectangle is no more than 556 inches. The length is 150 inches. Write an inequality and

find the possible widths for the rectangle
Mathematics
1 answer:
hoa [83]3 years ago
8 0
So perimeter<u><</u>556
permiter=2Legnth+2Width
so perimiter=2(legnth+width)

556/2<u>></u>Legnth+width
228<u>></u>legnth +width
legnth =150
so 228<u>></u>150+width
subtract 150 from both sides
78<u>></u>width
width cand be 78 or less but not 0 or negative



anoth way to do it is 556<u>></u>2(150)+2width
556<u>></u>300+2width
subtract 300 from both sides
256<u>></u>2width
divide both sides by 2
78<u>></u>width
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an equivalent function to f (x) = 2 (5) ^ {2x} is:

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