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kakasveta [241]
3 years ago
10

I CANT MISS ANYMORE PLEASE HELP!

Mathematics
1 answer:
Ivenika [448]3 years ago
8 0

Answer:

96

Step-by-step explanation:

Find the base area, which is d times c, and multiply it by the height b (not the slant height a!)

3 x 8 = 24

24 x 4 = 96

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The monthly salaries of a sample of 100 employees were rounded to the nearest ten dollars. they ranged from a low of $1,040 to a
never [62]
1720 - 1040 = 680
680/7 = 97.1

I would put them in intervals of 100




6 0
3 years ago
What is the form of the Pythagorean triple generator?​
stepladder [879]

Answer:(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)

Step-by-step explanation:

We can rewrite left side into right side form

(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)

we can expand it

(x^2+y^2)^2=x^4+x^2y^2+x^2y^2+y^4

(x^2+y^2)^2=x^4+y^4+2x^2y^2

we can add and subtract 2x^2y^2

(x^2+y^2)^2=x^4+y^4+2x^2y^2+2x^2y^2-2x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+2x^2y^2+2x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+4x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+(2xy)^2

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

4 0
3 years ago
Read 2 more answers
Guys please help! In triangle CDE, the measure of angle C is 90 degrees, side CD is 15 and DE is 3 more than CE. Find the length
AURORKA [14]
You can calculate it using the law of cosines: c^2=a^2+b^2-2*a*b*cos(C)

your triangle is
CD=15=a
CE=?=b
DE=CE+3=b+3=c
and C=90°

-> insert those values, with c substituted with b+3 to remove c

c^2=a^2+b^2-2*a*b*cos(C)
(b+3)^2=15^2+b^2-2*15*b*cos(90)
cos(90)=0->
(b+3)^2=15^2+b^2
b^2+2*3*b+3^2=225+b^2
6b+9=225
6b=216
b=36=CE

DE=CE+3=36+3=39
4 0
4 years ago
How do you write <br> 17<br> 25<br> as a percentage?
Sonja [21]

is that supposed to be written as a fraction and you are looking for a percentage?


5 0
4 years ago
Read 2 more answers
Distributive property 27+36
UkoKoshka [18]

Answer:

I think it will be equal to 63

Step-by-step explanation:

27+46=63

3 0
3 years ago
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