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masha68 [24]
3 years ago
15

I need help with this plz...Thanks

Mathematics
1 answer:
blagie [28]3 years ago
5 0

Answer:

YES

Step-by-step explanation:

==>Given:

=>Area to be painted = area of 1 long wall + area of 1 short wall = (3.49m*2.65m) + (2.98m*2.65m)

= 10.441 + 7.897

Area to be painted ≈ 18.34 m²

Cost of painting:

2.5L of paints costs £16 and covers 30m²

Therefore, litres of paint to cover 18.34 m² = (2.5L*18.34)/30 = 45.85/30 ≈ 1.5L

2.5L costs £16

Therefore, 1.5L costs = (16*1.5)/2.5 = 24/2.5 = £9.6

==>Area to be covered with wall paper = area of 1 long wall + area of 1 short wall ≈ 18.34m²

Cost of covering with wall paper:

Area of 1 roll = 52cm * 10m = 0.52m * 10m = 5.2m²

No of rolls to cover 18.34m² = 18.34m²/5.2m² ≈ 3.5 rolls

Cost of 1 roll = $10

Cost of 3.5 rolls = 3.5*10 = £35

Total cost required = £9.6 + £35 = £44.6

£44.6 is less than the budget of the tenant (£75).

Therefore, the tenant can decorate the room with the set budget.

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A carpenter is assigned the job of expanding a rectangular deck where the width is one-fourth the length. the length of the deck
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Alright, lets get started.

Suppose the original deck size: width = x feet

the width is one-fourth the length given in question means length = 4 x feet

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New dimensions, width = (x + 6)

new length = (4x+10)

So, new area will be = (x+6) * (4x+10) = 4x^{2} + 10 x + 24 x + 60 = 4x^{2} + 34 x + 60

the area of the new rectangular deck is 128 ft2 larger than the area of the original deck, means

4x^{2} + 128= 4x^{2} + 34 x + 60

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Hope it will help :)

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