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uranmaximum [27]
3 years ago
6

Are these answers correct? If not, what would the answers be?

Mathematics
1 answer:
Ludmilka [50]3 years ago
7 0
Yes you have the correct answers for each of the four problems. Nice work.

For anyone curious,
rd = removable discontinuity
id = infinite discontinuity
c = continuous
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yawa3891 [41]

All the answers are in the link

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1 year ago
An experiment has four equally likely outcomes: E1, E2, Es, and E.Round your answers to three decimal places. a. What is the pro
V125BC [204]

Answer:

a. 0.25

b. 0.50

c. 0.75

Step-by-step explanation:

P(E1) = 0.25

P(E2) = 0.25

P(Es) = 0.25

P(E) = 0.25

a. Since there are 4 outcomes with the same probability of occurring, the probability of E occurring is:

P(E) = \frac{1}{4}=0.25

b. The probability of any two outcomes occurring is twice the probability of a single outcome occurring

P(two\ outcomes) = 2*P(one\ outcome) = \frac{2}{4}=0.50

c. The probability of any three outcomes occurring can be written as 100% minus the probability of the remaining outcome occurring

P(three\ outcomes) = 1-P(one\ outcome) = 1-\frac{1}{4}=0.75

6 0
4 years ago
The angle θ lies in Quadrant II .
Andreyy89

let's keep in mind that, in the II Quadrant, cosine is negative and sine, is positive.

cosine is adjacent/hypotenuse, however the hypotenuse is simply a radius unit, and thus is never negative, so in the -(2/3) the negative must be the numerator, -2.


\bf cos(\theta )=\cfrac{\stackrel{adjacent}{-2}}{\stackrel{hypotenuse}{3}}\impliedby \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{3^2-(-2)^2}=b\implies \pm\sqrt{5}=b\implies \stackrel{\textit{II Quadrant}}{+\sqrt{5}=b}~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\sqrt{5}}}{\stackrel{adjacent}{-2}} \\\\\\ ~\hspace{34em}

6 0
4 years ago
Please helppppp!!!!!
BaLLatris [955]

Answer:

C

Step-by-step explanation:

Let g(x) be y

From the (1,4)

When x =1 y =?

These (2x)^2

(2 × 1)^2 = 2 ^2 = 4

5 0
4 years ago
One number is 8 greater than another. The product of the numbers is 48. Find the numbers.<br> ch
Naya [18.7K]
The numbers could be 20+28=48
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4 years ago
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