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nata0808 [166]
4 years ago
7

Waht is 2 to the eighth power

Mathematics
1 answer:
slava [35]4 years ago
6 0

Answer:

256

Step-by-step explanation:

2 to the 8th power is the same as 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2


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X^2 + 10x + 25 = 0<br><br><br>I feel like I've tried everything and I just don't get it.
loris [4]
If you are factoring it you can factor it into (x+5)^2
8 0
3 years ago
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Plz help me ........
Tju [1.3M]

Answer a is it

Step-by-step explanation

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=x%20%2B%20y%20%20%3D%2014%5C%5C%202x%20%2B%204y%20%3D%2018" id="TexFormula1" title="x + y = 1
alexgriva [62]

Answer:

x = 19, y = -5

Step-by-step explanation:

x + y = 14  => x= 14-y

2x + 4y = 18  => 2(x+2y)=18  => x+2y=9

x+2y=9 => (14 - y) + 2y = 9

14 + y = 9  => y = -5

x + (-5) = 14  => x=19

5 0
3 years ago
There are 1,200 students at Roosevelt middle school. There are 700 boys at the school. What percentage of the students at Roosev
Stella [2.4K]
Out of 1,200 students, 700 are boys. Therefore, the fraction would be \frac{700}{1200}.

To convert this into a percentage, divide 700 by 1,200.

\frac{700}{1200} = 0.583333 (or just 0.583 if you round)

Multiply 0.583 by 100 to get a percentage.

0.583 · 100 = 58.3

So, the percent of boys at the school is 58.3%.
4 0
3 years ago
A genetic experiment involving peas yielded one sample of offspring consisting of 409 green peas and 171 yellow peas. Use a 0.05
grigory [225]
The usual expectation for this kind of experiment is that the peas would yield green and yellow peas in a 3:1 ratio, or 75% green to 25% yellow. So your null hypothesis is that the proportion of yellow peas is p=0.25.

You're testing the claim that 26% of the offspring will be yellow, which means the alternative hypothesis is that the proportion of yellow peas is actually 0.26, or more generally that the expected proportion is greater than 0.25, or p>0.25.

The test statistic in this case will be

Z=\dfrac{\hat p-p_0}{\sqrt{\dfrac{p_0(1-p_0)}n}}

where p_0 is the proportion assumed under the null hypothesis, \hat p is the measured proportion, and n is the sample size. You have p_0=0.25, \hat p=\dfrac{171}{171+409}\approx0.29, and n=409+171=580, so the test statistic is

Z=\dfrac{0.29-0.25}{\sqrt{\dfrac{0.25\times0.75}{580}}}\approx2.2247

Because you're testing p>p_0, this is a right-tailed test, so the P-value is

\mathbb P(Z>2.2247)\approx0.0131

The critical value for a right-tail test at a 0.05 significance level is Z_\alpha\approx1.6449, which means the rejection region is any test statistic that is larger than this critical value. Since Z>Z_\alpha in this case, we reject the null hypothesis.

So the conclusion for this test is that the sample proportion is indeed statistically significantly different from the proportion suggested by the null hypothesis.
8 0
3 years ago
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