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mixas84 [53]
4 years ago
10

A new car is purchased for 19000 dollars. The value of the car depreciates at 11.25% per year. What will the value of the car be

, to the nearest cent, after 14 years?
Mathematics
1 answer:
ioda4 years ago
5 0

Answer: The answer is 3573.64

Step-by-step explanation:

Exponential Functions:

y=ab^x

a=starting value = 19000

r=rate = 11.25%=0.1125

Exponential Decay:

b=1-r=1-0.1125=0.8875

Write Exponential Function:

y=19000(0.8875)^x

Plug in time for x:

y=19000(0.8875)^14

y= 3573.6388855

Evaluate :

y≈3573.64

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Solve the equation 14y+82=6x-20 for x if y is 25
Leni [432]

Answer:

x= 226/3 or 75.33333333333333333333333333333

Step-by-step explanation:

14y+82=6x-20

y=25

Sub y=25 into 14y+82=6x-20

14y+82=6x-20

14(25)+82=6x-20

Calculate as follows:

14(25)+82=6x-20

350+82=6x-20

432=6x-20

Add twenty to both sides:

432+20=6x-20+20

452=6x-0

452=6x

Divide both sides by 6

452=6x

452/6=6x/6

452/6=x

x= 226/3 or 75.33333333333333333333333333333

8 0
3 years ago
Find the fifth term of (2x + y)10.
kkurt [141]
Im guessing the first answer
5 0
3 years ago
What is 9 2/5-8 1/3 I need to know for math tomorrow
patriot [66]

Answer:

1\frac{1}{15}

Step-by-step explanation:

Let's use a start by using common denominators. 9\frac{2}{5} = 9\frac{6}{15} and 8\frac{1}{3} = 8 \frac{5}{15}

Now, replace the original equation with the common denominators. 9\frac{6}{15} - 8\frac{5}{15}

Solve! 9\frac{6}{15} - 8\frac{5}{15} = 1\frac{1}{15}

8 0
3 years ago
What is typically used to quantitatively compare the effectiveness of layouts? A. trial and error B. load-distance model C. expo
Andre45 [30]

Answer:

B. load-distance model

Step-by-step explanation:

A. trial and error

Trial and error is "a fundamental method of problem solving. It is characterised by repeated, varied attempts which are continued until success". But this method is not the best in order to compare effectiveness of layouts

B. load-distance model

The load-distance method is a "mathematical model used to evaluate locations based on proximity factors. The objective is to select a location that minimizes the total weighted loads moving into and out of the facility. The distance between two points is expressed by assigning the points to grid coordinates on a map". And that's the correct option since we are trying to measure the effectiveness of layouts quantitatively.

C. exponential smoothing

This is "a rule of thumb technique for smoothing time series data using the exponential window function". Wheighting observations using the exponential function. But this is a techinique used to smooth s time series not to compare effectiveness of layouts.

D.process control charts

The Control Chart is a "graph used to study how a process changes over time with data plotted in time order". But we don't want to see how the process changes the objective is quantitatively compare the effectiveness of layouts, and this one is not the best option for this.

E. mean absolute deviation (MAD)

The median absolute deviation(MAD) is "a robust measure of how spread out a set of data is. The variance and standard deviation are also measures of spread, but they are more affected by extremely high or extremely low values and non normality". But again is just a measure of spread and not allow to compare effectiveness of layouts.

8 0
3 years ago
Consider the reflection of parallelogram PQRS across the line of reflection wy
solniwko [45]

Answer:

Consider the reflection of the parallelogram PQRS across the line of reflection wy if RR = 14 Then RZ= If SX=5 then = 5

Step-by-step explanation:

6 0
3 years ago
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