The probability of hitting the third ring is the same as finding what percentage is the area of the third ring out of the total area of the board.
The area of the third ring = The total area of the board - The area of the second circle.
Refer to the diagram below
The diameter for the whole circle = 32 in
The radius = 16 in
The area of the whole circle = π(16)² = 256π
The diameter for the second circle = 22 in
The radius = 11 in
The area of the second circle = π(11)² = 121π
The area of the third ring = 256π - 121π = 135π
Area of the third ring as a percentage of the total area =

= 52.7%
Answer:
81%
Step-by-step explanation:
Let 'L' be the dominant and 'l' e the recessive allele for ‘lazybuttness’.
Since ‘lazybuttness’ is an autosomal dominant condition, the 19% of students affected by the condition correspond to the homozygous dominant (LL) and heterozygous (Ll) genotypes. Therefore, the rest of the population has the homozygous recessive genotype (ll) and is not affected. The frequency of students not affected is:
F = 100% - 19% = 81%
Answer:
The pairs are;
t, v
2, 96
4, 32
5, 0
6, -32
7, -64
9, -128
Step-by-step explanation:
The given equation is f(t) = -16·t² + 160·t
We have, the velocity, v = d(f(t))/dt = d(-16·t² + 160·t)/dt = -32·t + 160
Which gives;
t, v
0, -32×(0) + 160 = 160
1, -32×(1) + 160 = 128
2, -32×(2) + 160 = 96
3, -32×(3) + 160 = 64
4, -32×(4) + 160 = 32
5, -32×(5) + 160 = 0
6, -32×(6) + 160 = -32
7, -32×(7) + 160 = -64
8, -32×(8) + 160 = -96
9, -32×(9) + 160 = -128
The given velocity values are;
96, -64, 32, 0, -128, -32 which correspond to 2, 7, 4, 5, 9, 6
The pairs are;
t, v
2, 96
4, 32
5, 0
6, -32
7, -64
9, -128
How many miles did the cars go? You can’t solve the question without that.